jyoticlub Posted September 2, 2006 Share Posted September 2, 2006 can please solve this although looks simple but i can't find my mistake An aircraft is flying at height of 3400m above the ground.If the angle subtended at a groung observation point by the aircraft positons 10secs apart is 30degrees ,what is the speed of the aircraft? tan30=10v\3400 well the ans i got is 196m/sec but actually the answer written is 182m/sec Link to comment Share on other sites More sharing options...
YT2095 Posted September 2, 2006 Share Posted September 2, 2006 I`ve moved this to the maths section for you, you`re more likely to get a faster answer than in the Mechanics section Link to comment Share on other sites More sharing options...
insane_alien Posted September 2, 2006 Share Posted September 2, 2006 you used altitude instead of the range to the aircraft from the ground post. Link to comment Share on other sites More sharing options...
ssd Posted February 4, 2007 Share Posted February 4, 2007 can please solve this although looks simple but i can't find my mistake An aircraft is flying at height of 3400m above the ground.If the angle subtended at a groung observation point by the aircraft positons 10secs apart is 30degrees ,what is the speed of the aircraft? tan30=10v\3400 well the ans i got is 196m/sec but actually the answer written is 182m/sec Hint: Consider the equilateral triangle with base=10v, and height=3400. So, half base=5v. Check that tan(15)=5v/3400, v is in mt/sec, angle in degrees. Link to comment Share on other sites More sharing options...
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