aommaster Posted December 5, 2003 Share Posted December 5, 2003 You know these questions when they ask you to find out how many triangle are there in the diagram? Well, is there an actual formula that can be used??? Link to comment Share on other sites More sharing options...
wolfson Posted December 5, 2003 Share Posted December 5, 2003 #ABC = (xS^t+yS^p+rS-(S mod 2)) / f The letters relate to colums if you send me the picture or attach the picture of the traingle(s), then ill be happy to transpose the equation for you.. Link to comment Share on other sites More sharing options...
aommaster Posted December 5, 2003 Author Share Posted December 5, 2003 umm... i don't really have a picture, i was just generalising, i just wanted to know if there was a formula. Can u explain to me exactly how to find the formula so that i could work it out by myself Link to comment Share on other sites More sharing options...
wolfson Posted December 5, 2003 Share Posted December 5, 2003 Could someone please help me find a picture of a triangle's with a triangle, a sequence of top line 1 triangle next two and so on.... This would be much appreciated Link to comment Share on other sites More sharing options...
aommaster Posted December 6, 2003 Author Share Posted December 6, 2003 I found one but of a differnt sequence Link to comment Share on other sites More sharing options...
wolfson Posted December 6, 2003 Share Posted December 6, 2003 Ok this sequence starts with one triangle (a), and ends with 7 on the end (n): So applying Sn. For Arithmetic Progressions: x(a+n)/2 A = first term 1, n = last sum (7), x =number of sequence lines (4) Sn. = 4(1+7)/2 = 16 (remember only the internal sequence triangles). Theorise: calculating 27 lines: 1, 3, 5, 7 (triangles going up at rate of 2 added to previous). Sp. = z -1 x d + 1 Z = Line number to find, m = constant sequence difference (2): 27 – 1 x d + 1 = 53 So the 27-sequence line would contain 53 triangles (internal). So then apply Sn. x(a+n)/2 A = first term 1, n = last sum (53), x =number of sequence lines (27) 27(1+53)/2 = 729. The total amount of internal triangle in 27 lines would be 729. I hope this helps. Link to comment Share on other sites More sharing options...
wolfson Posted December 6, 2003 Share Posted December 6, 2003 Oh yes and please feel free to comment or ask questions Link to comment Share on other sites More sharing options...
aommaster Posted December 7, 2003 Author Share Posted December 7, 2003 I think youve made a mistake. You only found the number of small triangle, i need you to find EACH AND EVERY triangle. There are bigger trinagle like the whole of the first and second row. lol Link to comment Share on other sites More sharing options...
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