kaseyface Posted May 10, 2006 Share Posted May 10, 2006 My problem is Simplify: [use absolute value symbols if necessary] Squareroot 75a2b3c. Link to comment Share on other sites More sharing options...
timo Posted May 10, 2006 Share Posted May 10, 2006 Is that a different display system than the decimal one or is that [math] \sqrt{75 a^2 b^3 c} [/math] ? Link to comment Share on other sites More sharing options...
kaseyface Posted May 10, 2006 Author Share Posted May 10, 2006 It's that problem you wrote. I couldn't figure out how to write my problem like that. Sorry if it was confusing! Link to comment Share on other sites More sharing options...
timo Posted May 10, 2006 Share Posted May 10, 2006 The key to your problem is using the fact that [math] \sqrt{xY} = \sqrt{x} \cdot \sqrt{Y} [/math]. Using that, try to pull out as many factors as possible. I´ll give you a first step, you´ll have to do the others yourself: [math] \sqrt{75a^2b^3c} = \sqrt{b^2} \cdot \sqrt{75a^2b^1c} = b \sqrt{75a^2bc} [/math] Link to comment Share on other sites More sharing options...
JustStuit Posted May 10, 2006 Share Posted May 10, 2006 If you still have trouble, separate it out to [math]\sqrt{(25)(3)a^2b^2bc}[/math] and see if that helps. Link to comment Share on other sites More sharing options...
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