ku Posted March 4, 2006 Share Posted March 4, 2006 Can someone show me in a step-by-step way how the following partial differentiations were obtained? Link to comment Share on other sites More sharing options...
m4rc Posted March 4, 2006 Share Posted March 4, 2006 I assume that you can differentiate Y with respect to L and get a dY/DL as a function of L and K. Then the tricky part is getting rid of the term in the square bracket. Express the term in the square bracket as a function of Y and alpha. Then substitute the expression you get for the term in the sqare bracket into your solution for DY/DL. Link to comment Share on other sites More sharing options...
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