Garfield Posted January 5, 2006 Share Posted January 5, 2006 I came up with a cheap formula to solve the surfice of any triangle. Though I'm not sure if it is correct. I wonder if you 1337 guys could check it.*points to sig* Link to comment Share on other sites More sharing options...

EvoN1020v Posted January 5, 2006 Share Posted January 5, 2006 I checked the formula by using c=5, b=3, a=4, but first, I used the [math]c^{2}=a^{2}+b^{2}[/math]. The surface area should be 5. Then I put in the variable with the known numbers, using this formula:[math]S_{triangle}=\frac{c\sqrt{b^2-\left(\frac{b^2-a^2+c^2}{2c}\right)^2}}{2}[/math]. I got a 6 for an answer following my calculation, so the formula would be right, if it have minus 1 like this: [math]S_{triangle}=\frac{c\sqrt{b^2-\left(\frac{b^2-a^2+c^2}{2c}\right)^2}}{2}-1[/math]. Therefore the answer would be 5, thus the surface area for a triangle with c=5, b=3, a=4. Link to comment Share on other sites More sharing options...

Garfield Posted January 5, 2006 Author Share Posted January 5, 2006 Ahem...[math] S_{triangle}=\frac{3*4}{2}=6 [/math] Don't you just hate it when that happens when doing calculations in your head. Link to comment Share on other sites More sharing options...

Rakdos Posted January 5, 2006 Share Posted January 5, 2006 [math']c^{2}=a^{2}+b^{2}[/math] That is the pythagorean theorem, not area. Link to comment Share on other sites More sharing options...

EvoN1020v Posted January 5, 2006 Share Posted January 5, 2006 WHOOPS! I mistakely used the pythagorean theorem to find the surface area of a triangle! Stupid me. The formula to find the surface area for a triangle is [math]A=\frac{1}{2}bh[/math]. Therefore, [math]\frac{1}{2}4*3[/math] is 6. So the big crazy formula is correct. Link to comment Share on other sites More sharing options...

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