AnarktTearia Posted December 23, 2005 Share Posted December 23, 2005 How anyone help me solve this? A druggist haspure alcohol and a 20% solution. How many gallons of each should be used in forming 4 gallons of a 30% solution? Link to comment Share on other sites More sharing options...
yammers Posted December 24, 2005 Share Posted December 24, 2005 Hi AnarktTearia, I'm not a math guy, but since no-one else has anwsered your problem I'll take a jab at it. 30% of 4 gallons is 1.2 gallons of alcohol, and 2.8 gallons of the (other). Since you'll be using 100% alcohol to increase the solution to 30% from 20%, you know that the 2.8 gallons of (other) is all that will be used; since the initial solution is 20% alc, then the 2.8 is 80%; the solution is 2.8/ 80% = 3.5 gallons of 20%. The rest (.50 gal) would be alcohol. Link to comment Share on other sites More sharing options...
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