TimbaLanD Posted November 17, 2005 Share Posted November 17, 2005 Hi all... I have a mass flow rate of 9800Kg/h substance through a heater. If the temperature of the substance is 0deg c and the min tem to be at 15deg c. Specific Heat Capacity: 1040 J/(kg*K) 1. how much heat do i need to apply? 2. How much power do i need to generate that heat? Anyone? Link to comment Share on other sites More sharing options...

Garfield Posted November 17, 2005 Share Posted November 17, 2005 I don't know if I understand this exrecise correctly(bad linguistic skills) but maybe this can help: [math]Q=\rho*m(T_1-T_2)[/math] and [math]N=\frac{A}{t}[/math]. So, if there's 9800kg of substance flowing through in 1h, you need [math]Q=\rho*9800(15-0) J[/math] of energy(note the K's and C's, though) and you need [math]N=\frac{\rho*9800(15-0) }{3600s}W[/math] of power, which probably is constant. [math]\rho[/math] is the Specific Heat Capacity([math]1040\frac {J}{kg*K}[/math] in this case. I'm not sure if this is what you want. Link to comment Share on other sites More sharing options...

TimbaLanD Posted November 17, 2005 Author Share Posted November 17, 2005 Thanks Garfield... Now i am going to work it out!! Where is that calculator!! Link to comment Share on other sites More sharing options...

## Recommended Posts

## Create an account or sign in to comment

You need to be a member in order to leave a comment

## Create an account

Sign up for a new account in our community. It's easy!

Register a new account## Sign in

Already have an account? Sign in here.

Sign In Now