anthropos Posted November 6, 2005 Share Posted November 6, 2005 I was reading my Maths textbook for fun when I came across the chapter on combinations and permutations. The textbook states that the number of permutations of n different objects is n! = n(n-1) (n-2) x...x 3 x 2 x 1 Then how should we define 0! so that the above result would stilll hold?? I checked 0! = 1. Hmm... can somebody enlighten me how this works? Link to comment Share on other sites More sharing options...
RyanJ Posted November 6, 2005 Share Posted November 6, 2005 I was reading my Maths textbook for fun when I came across the chapter on combinations and permutations. The textbook states that the number of permutations of n different objects is n! = n(n-1) (n-2) x...x 3 x 2 x 1 Then how should we define 0! so that the above result would stilll hold?? I checked 0! = 1. Hmm... can somebody enlighten me how this works? Maybe this can help Cheers, Ryan Jones Link to comment Share on other sites More sharing options...
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