mars_mhel Posted October 25, 2005 Share Posted October 25, 2005 I did the first part but then i have no clue on how to start the other.. here's the question: The reaction occurs at a temperature of 29.0 degress celsius and a pressure of 110kPa. Calculate the volume of gas that would produce if 720 mL of 1.35M sulfuric acid and 55.0g of zinc is used. H2SO4 + Zn --> ZnSO4 + H2 n=(1.35M)(0.72L) n= 55.0/65.38 n=0.972 mol n= 0.841 mol V= nRT/P V= (0.841*8.314*302.15) \ 110 V= 19.2L question b: When the reaction is part "a" occurs, 10.7 ml of water are produced. Calculate the percent error... i'm not sure how i can get water.. Link to comment Share on other sites More sharing options...
Tom Mattson Posted October 26, 2005 Share Posted October 26, 2005 i'm not sure how i can get water.. You can't get it from what was given. You have to have a reaction in which water is a product. Link to comment Share on other sites More sharing options...
LazerFazer Posted October 26, 2005 Share Posted October 26, 2005 Unless instead of H2SO4+Zn-->ZnSO4+H2 you get H2SO4+Zn-->ZnSO3+H2O. But don't see how that would be possible, since they give you the reaction itself. Link to comment Share on other sites More sharing options...
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