N00b Posted September 16, 2005 Share Posted September 16, 2005 I've been having some problems with these, if someone could help that's be nice. Perform the indicated operations and simplify. x^2 - x - 6 x^2 - 3x - 4 x^2 + 4x + 3 * x^2 - 4x + 3 (Note: This was originally a division problem but I flipped the last fraction to make it multiplication as I think your suppose to, that and I didn't know how to type the division sign.) Find the lowest common denominator: 5a - 15, 10a - 30 Solve the equation. 2 + x - 1 = x^2 - 1 x + 2 x + 3 x^2 + 5x + 6 Perform the indicated operations and simplify. Link to comment Share on other sites More sharing options...
DQW Posted September 16, 2005 Share Posted September 16, 2005 Show us what you've tried so far. Link to comment Share on other sites More sharing options...
N00b Posted September 16, 2005 Author Share Posted September 16, 2005 Link to comment Share on other sites More sharing options...
BigMoosie Posted September 16, 2005 Share Posted September 16, 2005 Q1) Factorise then cancel like terms on the top and bottom: [math]\frac{(x-3)(x+2)}{(x+3)(x+1)}*\frac{(x-4)(x+1)}{(x-3)(x-1)} = \frac{(x+2)(x-4)}{(x+3)(x-1)}[/math] Question 2, try factorising both, your common denominator will be the multiplacation of the alike terms: [math]5(a-3) = 2.5.(a-3)[/math] Question 3: Turn the left hand side into one fraction and factorise the right: [math] \frac{2(x+3)}{(x+2)(x+3)} + \frac{(x-1)(x+2)}{(x+3)(x+2)} = \frac{(x+1)(x-1)}{(x+3)(x+2)} [/math] [math] \frac{2(x+3) + (x-1)(x+2)}{(x+2)(x+3)} = \frac{(x+1)(x-1)}{(x+3)(x+2)} [/math] Cancel the denominator and work from there. Link to comment Share on other sites More sharing options...
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