Jump to content

Can someone help me solve this Algebra?


N00b

Recommended Posts

I've been having some problems with these, if someone could help that's be nice.

 

Perform the indicated operations and simplify.

x^2 - x - 6 x^2 - 3x - 4

x^2 + 4x + 3 * x^2 - 4x + 3

 

(Note: This was originally a division problem but I flipped the last fraction to make it multiplication as I think your suppose to, that and I didn't know how to type the division sign.)

 

 

 

Find the lowest common denominator:

5a - 15, 10a - 30

 

 

 

Solve the equation.

2 + x - 1 = x^2 - 1

x + 2 x + 3 x^2 + 5x + 6

 

 

Perform the indicated operations and simplify.

pic.php?u=5564WLGe0&i=40635

Link to comment
Share on other sites

Q1) Factorise then cancel like terms on the top and bottom:

 

[math]\frac{(x-3)(x+2)}{(x+3)(x+1)}*\frac{(x-4)(x+1)}{(x-3)(x-1)} =

\frac{(x+2)(x-4)}{(x+3)(x-1)}[/math]

 

Question 2, try factorising both, your common denominator will be the multiplacation of the alike terms:

 

[math]5(a-3) = 2.5.(a-3)[/math]

 

Question 3:

 

Turn the left hand side into one fraction and factorise the right:

 

[math]

\frac{2(x+3)}{(x+2)(x+3)} + \frac{(x-1)(x+2)}{(x+3)(x+2)}

= \frac{(x+1)(x-1)}{(x+3)(x+2)}

[/math]

 

[math]

\frac{2(x+3) + (x-1)(x+2)}{(x+2)(x+3)}

= \frac{(x+1)(x-1)}{(x+3)(x+2)}

[/math]

 

Cancel the denominator and work from there.

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.