sologuitar Posted December 1, 2022 Share Posted December 1, 2022 Let a = any integer Why does a^(1) = a? Link to comment Share on other sites More sharing options...

Eise Posted December 1, 2022 Share Posted December 1, 2022 See here: Link to comment Share on other sites More sharing options...

sologuitar Posted December 2, 2022 Author Share Posted December 2, 2022 14 hours ago, Eise said: See here: Sorry but I don't understand your descending powers in the denominator for each fraction. For example, you said (a^3) = (a^4)/(a•a^2). Can you further explain your work here? Link to comment Share on other sites More sharing options...

Eise Posted December 2, 2022 Share Posted December 2, 2022 5 hours ago, sologuitar said: Sorry but I don't understand your descending powers in the denominator for each fraction. For example, you said (a^3) = (a^4)/(a•a^2). Can you further explain your work here? No, I said: a^3 = (a^4)/a There are several other ways to see it, but they all are variations of the same theme: a^4 = a x a x a x a a^3 = a^4/a = (a x a x a x a)/a = a x a x a a^2 = a^3/a = (a x a x a)/a = a x a a^1 = a^2/a = (a x a)/a = a a^0 = a^1/a = a/a = 1 In short, the obvious rule is that with division of powers, you subtract the powers: (a^n)/a^m=a^(n - m). So when n = m: (a^n)/(a^n) = a^(n - n) = a^0. But dividing two equal numbers always gives 1. (Except 0^0, which can not be defined.) Link to comment Share on other sites More sharing options...

sologuitar Posted December 2, 2022 Author Share Posted December 2, 2022 3 hours ago, Eise said: No, I said: a^3 = (a^4)/a There are several other ways to see it, but they all are variations of the same theme: a^4 = a x a x a x a a^3 = a^4/a = (a x a x a x a)/a = a x a x a a^2 = a^3/a = (a x a x a)/a = a x a a^1 = a^2/a = (a x a)/a = a a^0 = a^1/a = a/a = 1 In short, the obvious rule is that with division of powers, you subtract the powers: (a^n)/a^m=a^(n - m). So when n = m: (a^n)/(a^n) = a^(n - n) = a^0. But dividing two equal numbers always gives 1. (Except 0^0, which can not be defined.) Thank you. A much better reply. Link to comment Share on other sites More sharing options...

## Recommended Posts

## Create an account or sign in to comment

You need to be a member in order to leave a comment

## Create an account

Sign up for a new account in our community. It's easy!

Register a new account## Sign in

Already have an account? Sign in here.

Sign In Now