Dhamnekar Win,odd Posted June 6, 2022 Share Posted June 6, 2022 Find the volume of the solid bounded by [math]z = x^2 + y^2 [/math] and [math] z^2 = 4(x^2 + y^2) [/math] My attempt to answer this question: [math] \displaystyle\int_0^{2\pi}\displaystyle\int_0^2\displaystyle\int_0^4 1 \rho^2 \sin{(\phi)} d\rho d\phi d\theta = -\frac{128\pi \cos{(2)}- 128\pi}{3}= 189.822143919[/math] Is this answer correct? Link to comment Share on other sites More sharing options...
Dhamnekar Win,odd Posted June 6, 2022 Author Share Posted June 6, 2022 (edited) I think my answer in the original post is incorrect. So, I want to correct it. My corrected answer is [math] \displaystyle\int_0^{2\pi}\displaystyle\int_0^2\displaystyle\int_0^4 r dz dr d\theta =16\pi [/math] Is this answer correct? Edited June 6, 2022 by Dhamnekar Win,odd Link to comment Share on other sites More sharing options...
Dhamnekar Win,odd Posted June 8, 2022 Author Share Posted June 8, 2022 Answers to all of the aforesaid questions are affirmative. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now