Casimir effect and cosmological constant

[stephaneww]

35 minutes ago, swansont said:

Once again, it sounds like you are just rearranging variables and constants without regard for any physics interactions or processes. e.g. there is no "Planck Force" as an interaction, it's just the expression of force using Planck units.

 

Let's see:

with :

S_Pl = l_Pl² Planck surface

1/S_Pl = 1/l_Pl² = zero point energy of the QFT

F_Pl/S_Pl = energy density of zero point energy of the QFT

the physical meaning is not in doubt here

so why would putting 1/S =Λ not make physical sense ?

Edited February 10, 2022 by stephaneww

[swansont]

14 hours ago, stephaneww said:

 

Let's see:

with :

S_Pl = l_Pl² Planck surface

1/S_Pl = 1/l_Pl² = zero point energy of the QFT

F_Pl/S_Pl = energy density of zero point energy of the QFT

the physical meaning is not in doubt here

so why would putting 1/S =Λ not make physical sense ?

What does any of this have to do with the Casimir effect?

[stephaneww]

8 hours ago, swansont said:

What does any of this have to do with the Casimir effect?

23 hours ago, stephaneww said:

We just have to pass the surface S on the other side of the equality of casimir effect with :
1/dS = Λ
and
dF = F_Pl = c⁴/G, Planck force

We have thus by the same trick as the change of side of the equality for the cosmological constant in the EINSTIEN equation to obtain the energy density of the cosmological constant.

We don't need physical plates in the cosmos anymore

 

once again :

in one side S is the surface of the plates, in the other side dF/dS is an energy density in Casimir effect egality

 

Edited February 11, 2022 by stephaneww

[swansont]

46 minutes ago, stephaneww said:

 

once again :

in one side S is the surface of the plates, in the other side dF/dS is an energy density in Casimir effect egality

 

Where are the plates? I though you agreed there are none, in cosmology.

[stephaneww]

of course there are no plates in cosmology

just as Λ was initially used to make the universe static to finally account for the acceleration of the expansion of the universe,

1/S = Λ changes the physical meaning of physical plates.

The fact remains that dF / dS keeps the physical meaning of an energy density (or of a pressure if you prefer)

Edited February 11, 2022 by stephaneww

[stephaneww]

to be synthetic :

S = l_Pl² is a surface (= plate for the Casimir effect)

1/S = 1/l_Pl² in QFT or 1/S = Λ in cosmology are energies

according to their side in the equality of the Casimir effect, their physical meaning is different.

I do not see anything more convincing

Edited February 12, 2022 by stephaneww