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Chemistry/Maths Beer Pouring Puzzle


studiot
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It's been some while since we had a weeend puzzle to chew on so here is a new one.

 

You enter the bar and are offered a 1200 ml jug of beer on the condition that you divide the beer exactly into halves by pouring it into a number of jugs until you have exactly half in one of them.
You are provided with two empty jugs of 800 and 500 ml capacity.
None of the jugs have any markings to indicate volume.
Other rules are that you may not discard any beer or use any further containers or weigh anything.

 

What is the minimum number of pouring steps to achieve this and what are they ?

 

Please put answers in a 'spoiler', available at the end of the input icon bar as an eye symbol.

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1 hour ago, John Cuthber said:

I presume that

  Reveal hidden contents

filling the 800, pour from it to fill the 500, leaving 300; drink that

repeat.

You drank 600 so there's 600 left

 

is considered cheating.

WRT beer in a bar, the word "discard" means pouring it anywhere EXCEPT someone's mouth. You may have found an exploitable loophole.

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17 hours ago, Phi for All said:

WRT beer in a bar, the word "discard" means pouring it anywhere EXCEPT someone's mouth. You may have found an exploitable loophole.

It might breach this

On 10/21/2021 at 10:42 AM, studiot said:

any further containers

or indeed.
 

 

On 10/21/2021 at 10:42 AM, studiot said:

you may not ... weigh anything.

My solution would probably stop me being weightless.

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19 hours ago, John Cuthber said:

I presume that


 

  Reveal hidden contents

filling the 800, pour from it to fill the 500, leaving 300; drink that

repeat.

You drank 600 so there's 600 left

 

is considered cheating.

 

I didn't think I'd ever give a +1 for cheating but there you go.

You did however start correctly, hopefully you are not too drunk to finish it correctly.

Edited by studiot
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