Dhamnekar Win,odd Posted October 11, 2021 Share Posted October 11, 2021 Link to comment Share on other sites More sharing options...
chenbeier Posted October 11, 2021 Share Posted October 11, 2021 Confusion with K equilibrium constant and k constant of rate law. Link to comment Share on other sites More sharing options...
exchemist Posted October 12, 2021 Share Posted October 12, 2021 (edited) 17 hours ago, Dhamnekar Win,odd said: Bear in mind that the rate expression depends on how the rate-determining step of the reaction mechanism arises. In the case of the decomposition of acetaldehyde, it tells you something about the reaction mechanism, in the pressure regime considered. Pressure can affect the order of reaction kinetics, cf. Lindemann-Hinshelwood mechanism. Secondly, nothing in the information supplied tells you the temperature at which these reactions are taking place. N2O5 is a gas above about 50C. Edited October 12, 2021 by exchemist Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now