joigus Posted December 12, 2020 Share Posted December 12, 2020 (edited) \[7={\color{red}1}\times2^{2}+{\color{red}1}\times2^{1}+{\color{red}1}\times2^{0}={\color{red}111}\] \[7={\color{red}1}\times2^{2}+{\color{red}1}\times2^{1}+{\color{red}1}\times2^{0}={\color{red}1}{\color{red}1}{\color{red}1}\] Edited December 12, 2020 by joigus Link to comment Share on other sites More sharing options...
joigus Posted December 12, 2020 Author Share Posted December 12, 2020 (edited) Test on hexadecimal multiplication table with matrix & colours. \[\begin{array}{cccccccccccccccccc} {\color{teal}\times} & {\color{red}0} & {\color{red}1} & {\color{red}2} & {\color{red}3} & {\color{red}4} & {\color{red}5} & {\color{red}6} & {\color{red}7} & {\color{red}8} & {\color{red}9} & {\color{red}a} & {\color{red}b} & {\color{red}c} & {\color{red}d} & {\color{red}e} & {\color{red}f} & {\color{red}10}\\ {\color{red}0} & {\color{purple}0} & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\ {\color{red}1} & 0 & {\color{purple}1} & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & a & b & c & d & e & f & 10\\ {\color{red}2} & 0 & 2 & {\color{purple}4} & 6 & 8 & a & c & e & g & 12 & 14 & 16 & 18 & 1a & 1c & 1e & 20\\ {\color{red}3} & 0 & 3 & 6 & {\color{purple}9} & c & f & 12 & 15 & 18 & 1b & 1e & 21 & 24 & 27 & 2a & 2d & 30\\ {\color{red}4} & 0 & 4 & 8 & c & {\color{purple}g} & 14 & 18 & 1c & 20 & 24 & 28 & 2c & 30 & 34 & 38 & 3c & 40\\ {\color{red}5} & 0 & 5 & a & f & 14 & {\color{purple}19} & 1e & 23 & 28 & 2d & 32 & 37 & 3c & 41 & 46 & 4b & 50\\ {\color{red}6} & 0 & 6 & c & 12 & 18 & 1e & {\color{purple}24} & 2a & 30 & 36 & 3c & 42 & 48 & 4e & 54 & 5a & 60\\ {\color{red}7} & 0 & 7 & e & 15 & 1c & 23 & 2a & {\color{purple}31} & 38 & 3f & 46 & 4d & 54 & 5b & 62 & 69 & 70\\ {\color{red}8} & 0 & 8 & g & 18 & 20 & 28 & 30 & 38 & {\color{purple}40} & 48 & 50 & 58 & 60 & 68 & 70 & 76 & 80\\ {\color{red}9} & 0 & 9 & 12 & 1b & 24 & 2d & 36 & 3f & 48 & {\color{purple}51} & 5a & 63 & 6c & 75 & 7e & 87 & 90\\ {\color{red}a} & 0 & a & 14 & 1e & 28 & 32 & 3c & 46 & 50 & 5a & {\color{purple}64} & 6e & 78 & 82 & 8c & 96 & a0\\ {\color{red}b} & 0 & b & 16 & 21 & 2c & 37 & 42 & 4d & 58 & 63 & 6e & {\color{purple}79} & 84 & 8f & 9a & a5 & b0\\ {\color{red}c} & 0 & c & 18 & 24 & 30 & 3c & 48 & 54 & 60 & 6c & 78 & 84 & {\color{purple}90} & 9c & a8 & b4 & c0\\ {\color{red}d} & 0 & d & 1a & 27 & 34 & 41 & 4e & 5b & 68 & 75 & 82 & 8f & 9c & {\color{purple}a9} & b6 & c3 & d0\\ {\color{red}e} & 0 & e & 1c & 2a & 38 & 46 & 54 & 62 & 70 & 7e & 8c & 9a & a8 & b6 & {\color{purple}c4} & d2 & e0\\ {\color{red}f} & 0 & f & 1e & 2d & 3c & 4b & 5a & 69 & 76 & 87 & 96 & a5 & b4 & c3 & d2 & {\color{purple}e1} & f0\\ {\color{red}10} & 0 & 10 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90 & a0 & b0 & c0 & d0 & e0 & f0 & {\color{purple}100} \end{array}\] \[\begin{array}{cccccccccccccccccc} {\color{teal}\times} & {\color{red}0} & {\color{red}1} & {\color{red}2} & {\color{red}3} & {\color{red}4} & {\color{red}5} & {\color{red}6} & {\color{red}7} & {\color{red}8} & {\color{red}9} & {\color{red}a} & {\color{red}b} & {\color{red}c} & {\color{red}d} & {\color{red}e} & {\color{red}f} & {\color{red}1\color{red}0}\\ {\color{red}0} & {\color{purple}0} & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\ {\color{red}1} & 0 & {\color{purple}1} & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & a & b & c & d & e & f & 10\\ {\color{red}2} & 0 & 2 & {\color{purple}4} & 6 & 8 & a & c & e & g & 12 & 14 & 16 & 18 & 1a & 1c & 1e & 20\\ {\color{red}3} & 0 & 3 & 6 & {\color{purple}9} & c & f & 12 & 15 & 18 & 1b & 1e & 21 & 24 & 27 & 2a & 2d & 30\\ {\color{red}4} & 0 & 4 & 8 & c & {\color{purple}g} & 14 & 18 & 1c & 20 & 24 & 28 & 2c & 30 & 34 & 38 & 3c & 40\\ {\color{red}5} & 0 & 5 & a & f & 14 & {\color{purple}1\color{purple}9} & 1e & 23 & 28 & 2d & 32 & 37 & 3c & 41 & 46 & 4b & 50\\ {\color{red}6} & 0 & 6 & c & 12 & 18 & 1e & {\color{purple}2\color{purple}4} & 2a & 30 & 36 & 3c & 42 & 48 & 4e & 54 & 5a & 60\\ {\color{red}7} & 0 & 7 & e & 15 & 1c & 23 & 2a & {\color{purple}3\color{purple}1} & 38 & 3f & 46 & 4d & 54 & 5b & 62 & 69 & 70\\ {\color{red}8} & 0 & 8 & g & 18 & 20 & 28 & 30 & 38 & {\color{purple}4\color{purple}0} & 48 & 50 & 58 & 60 & 68 & 70 & 76 & 80\\ {\color{red}9} & 0 & 9 & 12 & 1b & 24 & 2d & 36 & 3f & 48 & {\color{purple}5\color{purple}1} & 5a & 63 & 6c & 75 & 7e & 87 & 90\\ {\color{red}a} & 0 & a & 14 & 1e & 28 & 32 & 3c & 46 & 50 & 5a & {\color{purple}6\color{purple}4} & 6e & 78 & 82 & 8c & 96 & a0\\ {\color{red}b} & 0 & b & 16 & 21 & 2c & 37 & 42 & 4d & 58 & 63 & 6e & {\color{purple}7\color{purple}9} & 84 & 8f & 9a & a5 & b0\\ {\color{red}c} & 0 & c & 18 & 24 & 30 & 3c & 48 & 54 & 60 & 6c & 78 & 84 & {\color{purple}9\color{purple}0} & 9c & a8 & b4 & c0\\ {\color{red}d} & 0 & d & 1a & 27 & 34 & 41 & 4e & 5b & 68 & 75 & 82 & 8f & 9c & {\color{purple}a\color{purple}9} & b6 & c3 & d0\\ {\color{red}e} & 0 & e & 1c & 2a & 38 & 46 & 54 & 62 & 70 & 7e & 8c & 9a & a8 & b6 & {\color{purple}c\color{purple}4} & d2 & e0\\ {\color{red}f} & 0 & f & 1e & 2d & 3c & 4b & 5a & 69 & 76 & 87 & 96 & a5 & b4 & c3 & d2 & {\color{purple}e\color{purple}1} & f0\\ {\color{red}1\color{red}0} & 0 & 10 & 20 & 30 & 40 & 50 & 60 & 70 & 80 & 90 & a0 & b0 & c0 & d0 & e0 & f0 & {\color{purple}1\color{purple}0\color{purple}0} \end{array}\] Edited December 12, 2020 by joigus Link to comment Share on other sites 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joigus Posted December 13, 2020 Author Share Posted December 13, 2020 (edited) \[\begin{array}{cccccc} & & & {\color{red}0} & {\color{red}1} & {\color{red}1}\\ & & \times & {\color{red}1} & {\color{red}1} & {\color{red}1}\\ & & & 0 & 1 & 1\\ & & 0 & 1 & 1\\ & 0 & 1 & 1\\ & {\color{green}1} & {\color{green}0} & {\color{green}1} & {\color{green}0} & {\color{green}1} \end{array}\] Edited December 13, 2020 by joigus Link to comment Share on other sites More sharing options...
ahmet Posted December 16, 2020 Share Posted December 16, 2020 (edited) maybe something better exists..(html+css +js (+php)) Edited December 16, 2020 by ahmet Link to comment Share on other sites More sharing options...
Markus Hanke Posted December 19, 2020 Share Posted December 19, 2020 (edited) \[x^2\] Edited December 19, 2020 by Markus Hanke Link to comment Share on other sites More sharing options...
Sensei Posted December 19, 2020 Share Posted December 19, 2020 (edited) On 12/16/2020 at 9:00 PM, ahmet said: maybe something better exists..(html+css +js (+php)) ..you cannot use your own HTML+CSS+JS+PHP on 3rd party website like this forum.. You have to use what is built-in website. This part of the forum (The Sandbox) is for testing such built-in features. Permission to execute JS + PHP on a third party would allow deep surveillance of forum members, person identification, hacker attacks, money theft etc. Edited December 19, 2020 by Sensei Link to comment Share on other sites More sharing options...
ahmet Posted December 19, 2020 Share Posted December 19, 2020 6 minutes ago, Sensei said: ..you cannot use your own HTML+CSS+JS+PHP on 3rd party website like this forum.. You have to use what is built-in website. This part of the forum (The Sandbox) is for testing such built-in features. Permission to execute JS + PHP on a third party would allow deep surveillance of forum members, person identification, hacker attacks, money theft etc. this is correct ,I also sometimes add the mechanism of +TCP,UDP protocols and all the content relevant to this. but in spite of these details, I see many people using their own websites,though. Can we say that most of them were not sufficiently knowledgeable? About LaTeX: I have not used it so much and I was supposing that it would not contain good/shining colours. (i.e. not suitable for a good presentation) setting formulas, colours , borders , etc ...this is a part of programming that might require good work. Link to comment Share on other sites More sharing options...
joigus Posted December 19, 2020 Author Share Posted December 19, 2020 (edited) \[ \left( \frac{1}{\sqrt{1-v^2/c^2}}, \frac{v_x}{\sqrt{1-v^2/c^2}}, \frac{v_y}{\sqrt{1-v^2/c^2}}, \frac{v_z}{\sqrt{1-v^2/c^2}} \right) \] Edited December 19, 2020 by joigus Link to comment Share on other sites More sharing options...
joigus Posted December 22, 2020 Author Share Posted December 22, 2020 (edited) \[ \frac{\sqrt{FE_R} \left( \sqrt[4]{FE_R} \right)^2}{\frac{E_R}{c^2}} = \left( FE_R \right)^{\frac{1}{2}+\frac{2}{4}} \frac{1}{c^2} =\] \[ =\frac{FE_R}{\frac{E_R}{c^2}} =Fc^2 = \frac{G}{c^2}c^2 \] Edited December 22, 2020 by joigus Link to comment Share on other sites More sharing options...
joigus Posted December 22, 2020 Author Share Posted December 22, 2020 (edited) invisible braces: \[ {\left. \delta^{\mu} \right. }_{\nu}\] Edited December 22, 2020 by joigus Link to comment Share on other sites More sharing options...
Orion1 Posted February 9, 2022 Share Posted February 9, 2022 (edited) [math]\boxed{\color{blue}{\bigotimes} \; \int f(\color{blue}{n}) \; \text{SCIENCE} \color{blue}{\text{FORUMS}} \text{.NET}}[/math] Edited February 9, 2022 by Orion1 Link to comment Share on other sites More sharing options...
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