Jump to content

On the topic of Relativity of Simultaniety is LV/C^2 ever not = to L' vs L??

Recommended Posts

4 hours ago, can't_think_of_a_name said:

Or can Lv/c^2 = L?

Purely algebraically, this can only be true for L=0 (trivial case), or for v=c^2 (physically impossible).

Share this post

Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.