Sarahisme Posted August 14, 2005 Share Posted August 14, 2005 just wanted to make sure i am doing this correctly.... ok my answers are: (1) [math] \lambda_n=\frac{2L}{n}, \ n=1,2,3,... [/math] (2) [math] v=\sqrt{\frac{F}{\mu}} [/math] [math] \mu=\frac{M}{L} \ \ \ \ (mass \ per \ unit \ length) [/math] [math] f=\frac{v}{\lambda}=\frac{n\sqrt(\frac{F}{\mu})}{2L}=\frac{n\sqrt(F)}{2L\sqrt(\mu)} [/math] ok yep thats it (hopefully the latex stuff works, i cannot see it on my computer at the moment, so just tell me if it shows up incorrectly (or not at all) ) Cheers Sarah Link to comment Share on other sites More sharing options...
DQW Posted August 14, 2005 Share Posted August 14, 2005 Just one really tiny correction : [math] f_n=\frac{v}{\lambda _n}=\frac{n\sqrt(\frac{F}{\mu})}{2L}=\frac{n\sqrt(F)}{2L\sqrt(\mu)} [/math] I added a subscript to the frequency to indicate which mode it is for. The rest is all good. Link to comment Share on other sites More sharing options...
Sarahisme Posted August 15, 2005 Author Share Posted August 15, 2005 cool! thanks DQW! Link to comment Share on other sites More sharing options...
reyam200 Posted August 15, 2005 Share Posted August 15, 2005 ive never understood the symbols, i understand physics in plain english Link to comment Share on other sites More sharing options...
Kedas Posted August 15, 2005 Share Posted August 15, 2005 A small detail shouldn't the question be a wire between two points at distance L instead of a wire of L length? Because how can there be an amplitude if the whole wire is used up as n/2 times wave length. Link to comment Share on other sites More sharing options...
DQW Posted August 15, 2005 Share Posted August 15, 2005 Perhaps you (kedas) are neglecting the fact that the wire is capable of stretching elastically to accomodate the amplitude ? Link to comment Share on other sites More sharing options...
Kedas Posted August 15, 2005 Share Posted August 15, 2005 Perhaps you (kedas) are neglecting the fact that the wire is capable of stretching elastically to accomodate the amplitude ? yes elasticity is needed. I only want to say that the L in the formula is the distance between A and B. it's only a small detail like I said. Link to comment Share on other sites More sharing options...
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