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Geometry: Logic and Reasoning


Rachel Maddiee

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First, you need to multiply what you have prior bracket with what is inside of bracket
e.g. -3(a+3) = -3*a-3*3 = -3a-9

then the same with second one,

5(3-a)=5*3-5a=15-5a

then move the all numbers to the right side, changing signs

-50+9-15=-56

sum the all a on the left side

-3a-5a=-8a

so you have finally

-8a=-56

divide by -8 either side

a=-56/(-8)=56/8=7

ps. It's not geometry, but algebra. Linear equation with single unknown.

https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-solving-equations

 

Edited by Sensei
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