Rachel Maddiee Posted September 12, 2019 Share Posted September 12, 2019 Solve -3(a+3) +5 (3-a) = -50 I can’t apply Properties of Equality. Link to comment Share on other sites More sharing options...
studiot Posted September 12, 2019 Share Posted September 12, 2019 (edited) 1 hour ago, Rachel Maddiee said: Solve -3(a+3) +5 (3-a) = -50 I can’t apply Properties of Equality. Why not ? I make a = 7 Edited September 12, 2019 by studiot 1 Link to comment Share on other sites More sharing options...
Rachel Maddiee Posted September 12, 2019 Author Share Posted September 12, 2019 Can you show me ? Link to comment Share on other sites More sharing options...
Sensei Posted September 12, 2019 Share Posted September 12, 2019 (edited) First, you need to multiply what you have prior bracket with what is inside of bracket e.g. -3(a+3) = -3*a-3*3 = -3a-9 then the same with second one, 5(3-a)=5*3-5a=15-5a then move the all numbers to the right side, changing signs -50+9-15=-56 sum the all a on the left side -3a-5a=-8a so you have finally -8a=-56 divide by -8 either side a=-56/(-8)=56/8=7 ps. It's not geometry, but algebra. Linear equation with single unknown. https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-solving-equations Edited September 12, 2019 by Sensei 1 Link to comment Share on other sites More sharing options...
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