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Combustion


Gio_5

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Hello everyone,
I would like a helping hand for this exercise:

"A mixture of carbon monoxide, methane and nitrogen occupies a volume of 40 mL. Burning this mixture with an excess of oxygen, a volume of 42 mL is observed after cooling at room temperature and together the formation of 36 mL of dioxide of carbon. Determine the volume of each component of the mixture. "

I think this is the reaction: CO + CH4 + N2 + O2 --> CO2 + N2 + H2O, balanced: 2CO + 2CH4 + 5O2 --> 4CO2 + 4H2O removing N2 because acts as a spectator molecule.

Now, how do I proceed??

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21 hours ago, swansont said:

You have a balanced chemical equation, telling you how many moles of each reactant relates to moles of product. And you can convert from moles to volume.

Ok swansont, really thank you very much.

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