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Is there an experiment that verifies what happens when two unrelated matter waves collide?


scifimath

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I agree that the double slit experiment doesn't seem relevant as (in the quantum version) it involves a single particle rather than two independent ones.

You might find something here: https://iopscience.iop.org/article/10.1088/1367-2630/12/6/065029/meta

Or here: https://www.nature.com/articles/474586a

Or here: https://arxiv.org/search/?query="matter+wave+interference"&searchtype=all&abstracts=show&order=-announced_date_first

Or here: https://scholar.google.com/scholar?q=matter+wave+interference

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Is there an experiment that verifies what happens when two unrelated matter waves collide?

If the two objects are orbital electrons belonging to different atoms, the two may combine to form new molecular orbitals, one a bonding orbital and the other an antibonding orbital. These new orbitals have new wavefunctions, different to but formed from the original wavefunctions.

Edited by studiot
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5 minutes ago, studiot said:

If the two objects are orbital electrons belonging to different atoms, the two may combine to form new molecular orbitals, one a bonding orbital and the other an antibonding orbital. These new orbitals have new wavefunctions, different to but formed from the original wavefunctions.

..but he is talking about "matter wave" aka "de Broglie wavelength".. i.e. in diffraction or interference experiments with electrons you use de Broglie wavelength.

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6 minutes ago, scifimath said:

This is great (guess?), but do have any results besides orbitals?

You specified unrelated 'matter waves'

If you are using particles (matter waves) generated by the same source, how do you guarantee that they are unrelated?

If they are already in separate orbitals, this is guaranteed.

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Just now, scifimath said:

I think orbitals go by a slightly different set or rules. :/

Well explain what your rules are and what your objectives are.

Interaction of matter waves is an everyday common or garden event in this universe.

 

The point is twofold

(1)

To have a wave you need a wave equation to be satisfied.
There are varying degrees of sophistication of wave equations.

(2)

To pick out the appropriate solution to said wave equation you also need to apply boundary conditions.

 

In both (1) and (2) we normally use  appropriate versions to the situation.

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28 minutes ago, scifimath said:

This is great (guess?), but do have any results besides orbitals?

Consider how particles can decay into other particles when the original particle does not contain the other particles.

Consider how two protons can form  Higgs boson as one example.

This is just one example where the field excitation formalism of QFT makes more sense than thinking of particles as little billiard balls.

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Well, the point I'm heading to is that they aren't physical.

I want two atom cannons pointed at each other. Shoot a million at random angles, one of them is bound to hit another one ..right? Or do the two waves just ghost eachother?

 

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2 minutes ago, scifimath said:

Well, the point I'm heading to is that they aren't physical.

I want two atom cannons pointed at each other. Shoot a million at random angles, one of them is bound to hit another one ..right? Or do the two waves just ghost eachother?

 

If you must have atoms, rather than electrons, the gadget you want is called a field ion microscope.

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There are accelerators that use heavy ions. LHC and RHIC. But as these are high energy, they probably don’t show what you’re looking for. Cold atom experiments may be a better bet. (See below)

12 minutes ago, scifimath said:

I want them to be quantum waves when they "hit" each other.

deBroglie wave behavior isn’t wave function behavior, as Sensei already pointed out.

 

 

https://arxiv.org/pdf/1111.6196.pdf

“When the de Broglie wavelength is comparable to the interparticle spacing, the coherent matter waves associated with the various particles in the gas are forced to overlap, meaning (pictorially) that the number of independent quantum states in the gas becomes comparable to the number of gas particles. At this point, the quantum statistics of particles come into play in describing the nature of the gas.”

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