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Question about oleum


Larus99

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If you have 1 kg Oleum (20% SO3 dissolved in 100% H2SO4) then you have 200 g of sulfur trioxide and 800 g sulfuric acid.  With the molare weight of 80 g/mol for SO3  you get 2,5 mol.

You need also 2,5 mol water according H2O + SO3 => H2SO4 . This is equal to 45 g. So take 45 g = 45 ml water first!!  and add carefully the Oleum.

Edited by chenbeier
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Given the extremely violent reaction of  oleum with water it's probably better to add the oleum to ice.

It may also be a better bet to let it absorb water from the air (until it gains the right mass), but the fumes would be a problem.

 

Fundamentally, if you can't do basic chemistry like the calculation above, you shouldn't be working with oleum.

 

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