Oldand Dilis Posted July 3, 2019 Share Posted July 3, 2019 Can someone on a lab perform the double slit experiment counting the hits as specified below please, I am certain this is the solution, Where tpf = total photons fired hfw = hits on front wall hbw = hits on back wall If we assume a certain percent of photons always get through the slits say 10% then if 1000 photons are fired When recorded to see which slit they pass through the amount of hits will be tpf1000 = 900hfw +100hbw When not recorded to see which slits the photons pass through tpf1000 = 900hfw +100hbw+2(900)hbw or tpf1000 = 900hfw +100hbw+3(900)hbw or tpf1000 = 900hfw +100hbw+5(900)hbw or tpf1000 = 900hfw +100hbw+7(900)hbw Etc depending how far back the back wall is Showing the extra photons are arriving at the back wall in different time dimension when not recording which slit the photon is passing through. I give a full explanation as to why this is happening and why it indicates different time dimensions on my website doubleslitsolution.weebly.com Link to comment Share on other sites More sharing options...
swansont Posted July 3, 2019 Share Posted July 3, 2019 ! Moderator Note You already have posted this in another thread Link to comment Share on other sites More sharing options...
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