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On and on and on


anthropos

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I believe you can solve it by saying that:

 

[math]2^x = 3 \sqrt{3\sqrt{3\sqrt{3 \dots}}} = 3 \sqrt{2^x}[/math].

 

Haven't done one of these in a while though, so I could be wrong :)

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It's a pretty standard way of dealing with things like continued fractions and nested things in general. You'll still need logs to get the answer, which I think is [math]x = \frac{\log 3}{\log 2}[/math].

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AHA!!! I finally understand what's going on because we got back our papers and our dear teacher explained to us why! Aha, he was kind of frustrated because we only understood what was going on during his third attempt of explanation. Anyway, thanks Dave!

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AHA!!! I finally understand what's going on because we got back our papers and our dear teacher explained to us why! Aha, he was kind of frustrated because we only understood what was going on during his third attempt of explanation. Anyway, thanks Dave!

__________________

So you did understand him or you've already learnt the solution before his speaking?

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I mean at first I sent a message to Dave saying I don't understand, then later I seemed to grasp it (and not really at that same time...that ambiguity was horrible) and later with my teacher's aid, I totally grasp it!

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