gonsped Posted March 9, 2019 Share Posted March 9, 2019 I am proposing a short cooking demonstration with a propane torch inside a closed (no windows) conference room with ducted air conditioning. For this to be a safe demonstration - I am concerned to have the CO2 levels to be 1000ppm max. Here are my calcs + assumptions: Room is 6m x 4m x 2.4m = 57.6m3 Assume 400ppm CO2 initial concentration in the air Target max CO2 concentration of 1000ppm Ducted AC system brings in fresh air to keep CO2 @ 400ppm with a handful of occupants in the room Room temperature 25C 1kg of CO2 @ 25C = [22.7 mol x 0.0821 x (273 + 25)] / 1000 = 0.56m3 CO2 weight per m3 air @ 400ppm = (0.0004m3 x 1000) / 0.56 = 0.72g Weight of CO2 @ 400ppm in entire room = 57.6m3 x 0.72g = 41.4g Target max CO2 @ 1000ppm = 57.6m3 x 0.72g x 2.5 = 103.6g Combustion of C3H8 (Propane) - C3H8 + 5O2 = 3CO2 + 4H2O, ie. 44g propane + 160g oxygen = 132g CO2 + 72g H2O 1g of combustion of Propane = 3g CO2 produced (decrease of O2 concentration is negligible) Maximum burnable propane = (103.6g - 41.4g) / 3 = 20.7g Would I be correct to assume (I understand other variables can be at play) - that if I burn 20g of propane using a torch inside this room - I can keep the CO2 levels safe for the occupants in the room? Link to comment Share on other sites More sharing options...
chenbeier Posted March 19, 2019 Share Posted March 19, 2019 On safe side take a electrical fireplace. Link to comment Share on other sites More sharing options...
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