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Double series


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On 2/2/2019 at 10:13 PM, mathematic said:



[math]\sum_{i=1}^n\sum{j=1}^n\frac{|2i-A|}{2^kj+i}=\sum_{i=1}^n\frac{|2i-A|}{2^k}\sum{j=1}^n\frac{1}{j+2^{-k}i}\approx \sum_{i=1}^n\frac{|2i-A|}{2^k}(ln{n+2^{-k}i})-ln(2^{-k}i))[/math]. 


See if you can start here.  I am trying to use Latex - not working.



Edited by Strange
latex problem
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  • 4 months later...
On 2/7/2019 at 10:10 PM, mathematic said:

I can't get at my last post to try to fix it.  Essentially I tried to rearrange things so that the j summation could be carried out.

I think I fixed your Latex (no idea if it is correct or not!)

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