Jump to content

Double series


Steve@

Recommended Posts

On 2/2/2019 at 10:13 PM, mathematic said:

 

 

[math]\sum_{i=1}^n\sum{j=1}^n\frac{|2i-A|}{2^kj+i}=\sum_{i=1}^n\frac{|2i-A|}{2^k}\sum{j=1}^n\frac{1}{j+2^{-k}i}\approx \sum_{i=1}^n\frac{|2i-A|}{2^k}(ln{n+2^{-k}i})-ln(2^{-k}i))[/math]. 

 

See if you can start here.  I am trying to use Latex - not working.

 

 

Edited by Strange
latex problem
Link to comment
Share on other sites

  • 4 months later...
On 2/7/2019 at 10:10 PM, mathematic said:

I can't get at my last post to try to fix it.  Essentially I tried to rearrange things so that the j summation could be carried out.

I think I fixed your Latex (no idea if it is correct or not!)

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.