Guest shocker147 Posted June 29, 2003 Share Posted June 29, 2003 Can someone please help me solve this problem? dy/dx - [ycos(x)/1+2y^2] = 0 y(0) =1 Is this a combination of a differential equation and implicit differentiation? I'd appreciate any replies. Thanks Link to comment Share on other sites More sharing options...
Dave Posted June 30, 2003 Share Posted June 30, 2003 Just separate the variables out: int((1+2y^2)/y dy) = int(cos(x) dx) and solve it that way. Link to comment Share on other sites More sharing options...
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