Graviational force and escape velocity

[Butch 12]

Do gravitational force and escape velocity have a direct and constant relationship, specifically is the gravitational force at the schwarzild radius the same for any body? If so what is it?

[Strange 3139]

Escape velocity is given by [math]v_e = \sqrt{\frac{2GM}{r}}[/math] (https://en.wikipedia.org/wiki/Escape_velocity)

Where M is the mass of the planet (or whatever) and r is its radius. If you substitute the Schwarzschild radius ([math]r_s = \frac{2 G M}{c^2}[/math]) for r then you will find the result comes to c. (https://en.wikipedia.org/wiki/Schwarzschild_radius)

The equation for gravitational force is given by [math]F = G \frac{m M}{r^2}[/math]. As you can see, this decreases with r² rather than square root of r for escape velocity. It also depends on the mass (m) of the object. (https://en.wikipedia.org/wiki/Newton's_law_of_universal_gravitation)

So escape velocity and gravitational force are related but not in a direct way.

The acceleration due to gravity (g) is independent of the mass of the object (because acceleration is force/mass):  [math]g = G \frac{M}{r^2}[/math]

If we substitute this into the equation for escape velocity, we end up with:  [math]g = \frac{{v_e}^2}{2 r}[/math]

 

p.s. I wouldn't be too surprised if someone comes along and points out that I have made a mistake there somewhere...

Edited Friday at 03:23 PM by Strange

[Butch 12]

Thank you, you always make things pretty clear...