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Multivar equation help


Endy0816

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17 minutes ago, Endy0816 said:

Can anyone solve or help me find solutions for:

x + z - y = (0 or 15)

with x, y, and z ranging between 0 - 15?

Why not write C/C++ program?

#include <stdio.h>

int main( void )
{
	int counter = 1;
	for( int x = 0; x <= 15; x++ )
	{
		for( int y = 0; y <= 15; y++ )
		{
			for( int z = 0; z <= 15; z++ )
			{
				int result = x + z - y;
				if( ( result == 0 ) || ( result == 15 ) )
				{
					printf( "%d. X=%d Y=%d Z=%d\n", counter, x, y, z );
					counter++;
				}
			}
		}
	}
	return( 0 );
}

                                   

 

It generated 272 results, check results.txt in Release folder.

MultivarEquationHelp.zip

 

Edited by Sensei
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49 minutes ago, Sensei said:

Why not write C/C++ program?


#include <stdio.h>

int main( void )
{
	int counter = 1;
	for( int x = 0; x <= 15; x++ )
	{
		for( int y = 0; y <= 15; y++ )
		{
			for( int z = 0; z <= 15; z++ )
			{
				int result = x + z - y;
				if( ( result == 0 ) || ( result == 15 ) )
				{
					printf( "%d. X=%d Y=%d Z=%d\n", counter, x, y, z );
					counter++;
				}
			}
		}
	}
	return( 0 );
}

                                   

 

It generated 272 results, check results.txt in Release folder.

MultivarEquationHelp.zip

 

Thank you. Seemed relatively simple at first. I was able to find a number of solutions myself, but the inner positions where no coordinate is zero or 15 were giving me a headache.

 

 

Edited by Endy0816
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  • 2 weeks later...
On ‎2‎/‎18‎/‎2018 at 4:45 PM, Endy0816 said:

Can anyone solve or help me find solutions for:

x + z - y = (0 or 15)

with x, y, and z ranging between 0 - 15?

I assume x, y, and z must be integers.

  First x+ z- y= 0.

If x= 0 then z-  y= 0 so z= y.

(0, 0, 0), (0, 1, 1), (0, 2, 2), ..., (0, 15, 15)

If x= 1 then z- y= -1 so z= y- 1

(1, 1, 0), (1, 2, 1), (1, 3, 2), ..., (1, 15, 14)

If x= 2 then z- y= 2 so z= y- 2

(2, 2, 0), (2, 3, 1), (2,  4, 2), ...., (2, 14, 12)

continue.

,

 

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