Vmedvil Posted December 26, 2017 Share Posted December 26, 2017 (edited) Another Post, gave me this idea, for a different way to write this that Mainstream physics would accept and would be simpler. start with 4-D Invariant SR Time-space. ds2 = dx2 + dy2 + dz2 - (Cdt)2 Quantum Equivalence. ∇ =d2/dx2 + d2/dy2 + d2/dz2 = d2(1/dx2 + 1/dy2 + 1/dz2) dxψ2 + dyψ2 + dzψ2 = (d2/∇) Schrodinger equation Solve for ∇ ∇ = ((iħ(d/dt)ψ[r,t] - V[r,t]ψ[r,t])/((ħ2/2M)ψ[r,t]))1/2 Now for the Hard part the Energy Stress Tensor (dxψ2 + dyψ2 + dzψ2) - (dxTuv2 + dyTuv2 + dzTuv2) = 0 Sx2/θx2 = dx2 Δx = ((F/M) * Δt2) dxx = ((σxxAxx/M) * dt2) (Sx2/θx2)+ (Sy2/θy2) + (Sz2/θz2) - ((σxxAxx/M) * dt2)2 - ((σxyAxy/M) * dt2)2 - ((σxzAxz/M) * dt2)2 - ((σyxAyx/M) * dt2)2 - ((σyyAyy/M) * dt2)2 - ((σyzAyz/M) * dt2)2 - ((σzxAzx/M) * dt2)2 -((σzyAzy/M) * dt2)2 - ((σzzAzz/M) * dt2)2 = dxTuv2 + dyTuv2 + dzTuv2 Lastly Invariant Quantum Relativistic 4-D Time-space. ds2 = (dxψ2 + dyψ2 + dzψ2) - (dxTuv2 + dyTuv2 + dzTuv2) - (Cdt)2 Add SR ds2 = (dxψ2 + dyψ2 + dzψ2) - (dxTuv2 + dyTuv2 + dzTuv2) - (Cdt')2 V2 = VE2 - VΛ2 VΛ2 = H2d(Kiloparsec)2 VE2 = 2(∑Enet/M) Useful equations for θ Useful Energy Equations for ∑Enet = E1 + E2 + E3.... + E∞ Edited December 26, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
Vmedvil Posted December 26, 2017 Author Share Posted December 26, 2017 (edited) One more Edited December 26, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
Vmedvil Posted December 26, 2017 Author Share Posted December 26, 2017 (edited) To put it in the Similar form as Energy Density in the tensor, but you can measure much more with this version as it is not limited to this form. VE2 = 2(∑Enet/M) Electric Field Strength and Magnetic Dipole Moment. ∑Enet = EQdx + μB Electric Field Magnetic Dipole moment μ Magnetic Field B Edited December 26, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
Vmedvil Posted December 26, 2017 Author Share Posted December 26, 2017 (edited) http://hydrogen.physik.uni-wuppertal.de/hyperphysics/hyperphysics/hbase/rotq.html I am starting to realize another useful equation. ωx2Vx2 = dx2 ωy2Vy2 = dy2 ωz2Vz2 = dz2 Which is another form of this. (ωz2Vz2)+ (ωy2Vy2) + (ωx2Vx2) - ((σxxAxx/M) * dt2)2 - ((σxyAxy/M) * dt2)2 - ((σxzAxz/M) * dt2)2 - ((σyxAyx/M) * dt2)2 - ((σyyAyy/M) * dt2)2 - ((σyzAyz/M) * dt2)2 - ((σzxAzx/M) * dt2)2 -((σzyAzy/M) * dt2)2 - ((σzzAzz/M) * dt2)2 = dxTuv2 + dyTuv2 + dzTuv2 Edited December 26, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
swansont Posted December 26, 2017 Share Posted December 26, 2017 ! Moderator Note Is there a point to this, or are you just posting a bunch of equations and pictures? Link to comment Share on other sites More sharing options...
Vmedvil Posted December 26, 2017 Author Share Posted December 26, 2017 1 minute ago, swansont said: ! Moderator Note Is there a point to this, or are you just posting a bunch of equations? Oh, I am playing with something. Link to comment Share on other sites More sharing options...
Vmedvil Posted December 26, 2017 Author Share Posted December 26, 2017 (edited) Does anyone know what a Sqaure Radians sqaure meter per Hypersecond means in the same context as momentum density? Radian2 Meter2 / Second4 = ??? What is that a unit of? 9 minutes ago, Vmedvil said: Does anyone know what a Sqaure Radians sqaure meter per Hypersecond means in the same context as momentum density? Radian2 Meter2 / Second4 = ??? What is that a unit of? Oh I see what this is screwed up LOL This wrong algebra mistake. ωx2Vx2 = dx2 ωy2Vy2 = dy2 ωz2Vz2 = dz2 Which is another form of this. (ωz2Vz2)+ (ωy2Vy2) + (ωx2Vx2) - ((σxxAxx/M) * dt2)2 - ((σxyAxy/M) * dt2)2 - ((σxzAxz/M) * dt2)2 - ((σyxAyx/M) * dt2)2 - ((σyyAyy/M) * dt2)2 - ((σyzAyz/M) * dt2)2 - ((σzxAzx/M) * dt2)2 -((σzyAzy/M) * dt2)2 - ((σzzAzz/M) * dt2)2 = dxTuv2 + dyTuv2 + dzTuv2 Corrected form which actually makes sense. ωx2/Vx2 = dx2 ωy2/Vy2 = dy2 ωz2/Vz2 = dz2 Which is another form of this correct. (ωx2/Vx2) + (ωy2/Vy2) + (ωz2/Vz2) - ((σxxAxx/M) * dt2)2 - ((σxyAxy/M) * dt2)2 - ((σxzAxz/M) * dt2)2 - ((σyxAyx/M) * dt2)2 - ((σyyAyy/M) * dt2)2 - ((σyzAyz/M) * dt2)2 - ((σzxAzx/M) * dt2)2 -((σzyAzy/M) * dt2)2 - ((σzzAzz/M) * dt2)2 = dxTuv2 + dyTuv2 + dzTuv2 Edited December 26, 2017 by Vmedvil Link to comment Share on other sites More sharing options...
Vmedvil Posted December 27, 2017 Author Share Posted December 27, 2017 Well, I fused all this. Link to comment Share on other sites More sharing options...
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