Why don't Proton and Anti-proton collisions produce 3 Neutral Pions.

[Mordred]

As all constituent particles that comprise the proton/antiproton annihilate. This includes all conserved quantities, such as spin, color/ charge/ energy/momentum are annihilated so it becomes a full annihilation.

This allows any particles to be formed afterward provided energy/mass does not exceed the total energy of the two. This includes the monentum of the created particles.

(That is the sentence sum of conserved quantities equals zero indicates in above link).

Edited December 26, 2017 by Mordred

[Vmedvil]

9 minutes ago, Mordred said:

As all constituent particles that comprise the proton/antiproton annihilate. This includes all conserved quantities, such as spin, color/ charge/ energy/momentum are annihilated so it becomes a full annihilation.

This allows any particles to be formed afterward provided energy/mass does not exceed the total energy of the two. This includes the monentum of the created particles.

(That is the sentence sum of conserved quantities equals zero indicates in above link).

So, then it is not bound to the standard rules for the generation of mesons then as Singlets. That is fine then those other modes are acceptable. 

Edited December 26, 2017 by Vmedvil

[Mordred]

correct. Though its more accurate to state that the conservation laws of the Eightfold way are satisfied including those involved in the baryon octic/nonet

Edited December 26, 2017 by Mordred

[Vmedvil]

6 hours ago, Mordred said:

correct. Though its more accurate to state that the conservation laws of the Eightfold way are satisfied including those involved in the baryon octic/nonet

Got ya, so it goes octet instead of Singlet and not state 9, but 7 or 8 of octet. It is insane what you forget in 3 years of not using it, I had forgotten about octet states 7 and 8.

Making all of these states correct whether using octet states 7,8, or 9(Which is singlet)

Question Answered by Mordred.

Edited December 26, 2017 by Vmedvil