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Is this a new number ?


conway
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In every R there exists an integer zero element ( -0 )

( -0 )  =/=  0

|0| = |-0|

( -0 ) : possesses the additive identity property 

( -0 ) : does not possess the multiplication property of 0

( -0 ) : possesses the multiplicative identity property of 1 

The zero elements ( 0 ) and ( -0 ) in an expression of division can only exist as: (0)/( -0 )

 

0 + ( -0 ) = 0 = ( -0 ) + 0

( -0 ) + ( -0 ) = 0 

1 + ( -0 ) = 1 = ( -0 ) + 1

 

0 * ( -0 ) = 0 = ( -0 ) * 0

1 * ( -0 ) = 1 = ( -0 ) * 1

n * ( -0 ) = n = ( -0 ) * n

 

Therefore, the zero element ( -0 ) is by definition also the multiplicative inverse of 1 .

 

And as division by the zero elements requires ( - 0 ) as the divisor ( x / ( -0 )) is defined as the quotient ( x ) .

 

0 / n = 0

0 / ( -0 ) = 0

n / ( -0 ) = n

 

0 / 1 = 0

1 / ( -0 ) = 1

1 / 1 = 1

 

( 1/( -0 ) = 1 )

 

The reciprocal of ( -0 ) is defined as 1/( -0 )

 

1/(-0) * ( -0 ) = 1

 

(-0)^(-1) = ( 1/( -0 ) = 1

 

(-0)(-0)^(-1) = 1 = ( -0 )^(-1)

 

Any element raised to ( -1 ) equals that elements inverse.

 

0^0 = undefined

0^(-0) = undefined

1^0 = 1

1^(-0) = 1

 

Therefore, all expressions of ( -0 ) or ( 0 ) as exponents or as logarithms are required to exist without change.

Therefore, division by zero is defined.

Therefore, the product of multiplication by zero is relative to which integer zero is used in the binary expression of multiplication.

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13 minutes ago, Sensei said:

It gave 1 on my calculator..

 

https://www.math.hmc.edu/funfacts/ffiles/10005.3-5.shtml

https://brilliant.org/wiki/what-is-00/

The point being that "whatever" it is....

All representations of (-0) as exponents and logarithms work like 0 and without change from 0

thank you for your time and reply

Edited by conway
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