Jeannette98 Posted October 18, 2017 Share Posted October 18, 2017 I am a first year undergraduate and in my inorganic module we have recently undertaken a practical to find out various oxidation states of Vanadium. To start we made a stock solution by dissolving 2g of ammonium metavanadate (V) with 1.0 mol.dm-3 20 cm3 of sodium hydroxide. This we then added 35.0 cm3 sulphuric acid (1.0 mol.dm-3 ) and made the volume up to 250cm3 with deionised water. It was after the addition of the sulphuric acid that we observed the yellow solution and a red/brown precipitate/solid that then settled to the bottom of the volumetric flask. The solution was meant to be yellow with none of this precipitate so our initial thoughts are that a salt has been formed but to no avail have we found out what it is. Does anyone have any ideas of what was formed? Thank you in advance ! Link to comment Share on other sites More sharing options...
John Cuthber Posted October 19, 2017 Share Posted October 19, 2017 Vanadium pentoxide is red and not very soluble in water. Link to comment Share on other sites More sharing options...
Fuzzwood Posted October 19, 2017 Share Posted October 19, 2017 Metavanadate can only exist in basic solutions. Trying to make vanadyl sulphate is a tricky process. Link to comment Share on other sites More sharing options...
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