Sara Taboni Miller Posted August 26, 2017 Share Posted August 26, 2017 (edited) The space shuttle orbits 300 km above Earth surface , that has radius 6400 km . What is the gravitational acceleration experienced by the space shuttle ? Answer is 8.9 m/s^2 . I'm trying to equal mv ^2 / r = mMG/r^2 , where v^2/r is "a", so that I get a= mMG/r .. and I put r= 6400+300 but it isn't correct.. just a hint would be great , thank you in advance! Edited August 26, 2017 by Sara Taboni Miller Link to comment Share on other sites More sharing options...
Endy0816 Posted August 26, 2017 Share Posted August 26, 2017 Think it requires: mg=(mMG)/r^2 and ma = (mMG)/(r+300)^2 not 100% sure though. Generally doesn't seem like you have enough knowns from only the information provided. 1 Link to comment Share on other sites More sharing options...
swansont Posted August 26, 2017 Share Posted August 26, 2017 You already have ma = GMm/r^2 M is the mass of the earth. You know the radius. G is a constant. 1 Link to comment Share on other sites More sharing options...
Sara Taboni Miller Posted August 26, 2017 Author Share Posted August 26, 2017 Thanks a lot! Got it now ! Link to comment Share on other sites More sharing options...
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