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Proof Using Congruent Triangles


NSX

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Can someone check over my proof please?

Thanks.

I'm using the delta symbol to signify triangle :)

 

Question: S is the midpoint of side QR of :delta: PQR. QT & RW are drawn perpendicular to PS or PS extended. Prove that QT=RW:

 

Here's my sol'n:

 

In :delta: QTS & :delta: RWS:

1. QS = RS (given)

2. Angle QTS = Angle RWS (given)

3. Angle TSQ = Angle WSR (Opp. Angle Theorem)

4. Therefore :delta: QTS :cong: :delta: RWS (Angle Angle Side) (State1, S2, S3)

5. Therefore QT=RW

 

Thanks. It's for a hw presentation for Monday.

 

I've attached a jpeg of what the question looks like:

congruence.jpg

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