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Sarahisme

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hey, just double checking this stuff (i have only just begun this topic in maths and so i am a little shaky on it)

 

is the answer to this:

 

i) no , because the zero vector is not in the set H.

 

ii) yes, but i don't know how to explain why, i guess if you let s and t be zero, then the zero vector is part of the set L , and obviously if you add any two vectors it will still be in L and if you multiple by a scalar it will be too...

 

anyways, yeah as i said, i'm a greenhorn with this stuff, so take pity :P

 

Sarah

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ii) yes, but i don't know how to explain why, i guess if you let s and t be zero, then the zero vector is part of the set L

 

Yes.

 

 

 

and obviously if you add any two vectors it will still be in L and if you multiple by a scalar it will be too...

 

so you've got a vector space, and all is well - it;s the span of the vectors (1,2,1) and (3,3,6)

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