vedmecum
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Everything posted by vedmecum
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Hello! We have created a science forum. Researchers, professors, post graduate students and undergraduate students are invited to join/register our forum.
http://science.forumakers.com/
This is the link to my forum. It is still under construction and will be fully active from 1is august. Last date of registration is 15th august, so please join it as soon as possible. It will be a great pleasure for me, if you join it.
Nikhil aggarwal
University of Delhi, India
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Hello! We have created a science forum. Researchers, professors, post graduate students and undergraduate students are invited to join/register our forum.
http://science.forumakers.com/
This is the link to my forum. It is still under construction and will be fully active from 1is august. Last date of registration is 15th august, so please join it as soon as possible. It will be a great pleasure for me, if you join it.
Nikhil aggarwal
University of Delhi, India
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Hello! We have created a science forum. Researchers, professors, post graduate students and undergraduate students are invited to join/register our forum.
http://science.forumakers.com/
This is the link to my forum. It is still under construction and will be fully active from 1is august. Last date of registration is 15th august, so please join it as soon as possible. It will be a great pleasure for me, if you join it.
Nikhil aggarwal
University of Delhi, India
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up to my knowledge there must be a correction in your statement . d-orbitals are not poorly shielded but they shield poorly . This result in slightly decrease in energy of outer orbitals electron . for energy comparison http://www.chemguide.co.uk/atoms/properties/atomorbs.html
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i don't think that its -O-S(O)Cl- is the leaving group in case of SOCl2 and same for PCl5 , have a look on mech. http://www.cem.msu.edu/~reusch/VirtualText/Images2/alcolrx1.gif
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Potassium manganate --> Potassium permanganate HELP
vedmecum replied to jerryshizzle123's topic in Inorganic Chemistry
hi jerryshizzle123 , you said that u end up with MnO2 , these may be because of reaction condition which you had taken . Potassium permanganate is manufactured on a large scale from manganese dioxide, which is fused with potassium hydroxide and heated in air or with potassium nitrate (a source of oxygen). This leads to the formation of potassium manganate, which on electrolytic oxidation in alkaline solution gives potassium permanganate. MnO2 + 2OH− + O2 → MnO42− + H2O so instead of taking acidic medium try basic medium so in case MnO2 form , it will further electrolyzed to KMnO4 . -
The carbon atom of a carboxyl group is in a relatively high oxidation state. Reduction to a 1º-alcohol takes place rapidly on treatment with the powerful metal hydride reagent, lithium aluminum hydride, as shown by the following equation. One third of the hydride is lost as hydrogen gas, and the initial product consists of metal salts which must be hydrolyzed to generate the alcohol. These reductions take place by the addition of hydride to the carbonyl carbon, in the same manner for aldehydes and ketones. The resulting salt of a carbonyl hydrate then breaks down to an aldehyde that undergoes further reduction. 4 RCO2H + 3 LiAlH4 ether__> 4 H2 + 4 RCH2OM + metal oxides H20__> 4 RCH2OH + metal hydroxides.
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Addition of a hydride anion to an aldehyde or ketone would produce an alkoxide anion, which on protonation should yield the corresponding alcohol. Aldehydes would give 1º-alcohols (as shown) and ketones would give 2º-alcohols. RCH=O + H:(–) RCH2O(–) + H3O(–) RCH2OH practical source of hydride-like reactivity are the complex metal hydrides lithium aluminum hydride (LiAlH4). so LiAlH4 reduces all aldehydes and ketones .
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:-)why you wanna do this by electrolysis as these is both time consuming and require precision too . add those reagents which can form insoluble complexes with calcium and magnesium .
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:-)acetone by itself is an excellent solvent . i am not providing you complete ans , just a hint for you :- polar solute dissolve in polar solvent and non polar solute in non polar solvent . or ionic substances are soluble in ionic solvents and same for covalent .
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Tartaglia ,may be your ans. is correct to some extent but mine guess was also correct , you can verify it from the following links:- 1. http://www.chemguide.co.uk/inorganic/complexions/ligandexch.html 2. http://www.britannica.com/EBchecked/topic/136410/coordination-compound/277812/Substitution#ref=ref1008332 3. pages 706-710 http://books.google.com/books?id=ocKWuxOur-kC&pg=PA701&lpg=PA701&dq=substition+reaction+in+inorganic+chemistry&source=bl&ots=M7v4IiixEZ&sig=BaCbUwt8vT5_f6C5JEwlTC-PG7o&hl=en&ei=5t_mSbTWLsuHkQXy6pWbBw&sa=X&oi=book_result&ct=result&resnum=9#PPA711,M1 . :-)
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i don't know correct ans . but acc. to me its n't because of NO but due to formation of pentavalent ( sp3d hybridization ) transition state (as in your case) which acc. to Werner theory is highly unstable so complex again get its tetravalent state .
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definitely because of vacant d-orbital . let me provide you 2 hint 1 . there is a difference between hydration and hydrolysis . 2 . there is a formation of pentavalent transition state in sn2 type reaction but due to small size of carbon atom and limit of using only s and p orbital it again goes to tetravalent state . :-)
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okay this unravel 1st situation and what about second because to balance UC reaction we need almost double amount of Cl- , upto my knowledge CaCl+ is less stable than CaCl2 . Merged post follows: Consecutive posts merged both u and john are correct . you are talking about beta- decay and john has given an example of beta+ decay .
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:-) finally we reach at that point where i think we need to discuss more of chemistry as mine first ques. still not completely unravel . from the above posts what i concluded is that reaction will take place but the major ques. which struck in my hypothalamus is how reaction will balance by itself ? because if , for ex , we take uranium oxide in which uranium is in x+ oxidation state and we end with oxide of different element in +y oxidation state then how stiochiometry will be maintained . there will be 2 or more situation possible:- 1. new comp. have lesser no. of oxygen , then where the remaining oxygen will go ? . will we get free oxygen (if we took uranium oxide) ? if so then isn't amazing ? 2. if new comp. have higher no. of oxygen then from where it comes ?
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i agree with you as per K-37 (that we get noble element in last ) is concerned but i think we can't apply it universally for all radioactive substance . for example log on http://wiki.answers.com/Q/What_is_the_decay_products_of_uranium_238 and http://www.atral.com/U2381.html and there are many more links which indicates that the end product will be lead-206 . so now why not oxide of lead -206 form or it may form ?
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sorry because two of you have taken my ques. in a different sense but my exact ques. is what is written above . this is first time when i have no idea . Merged post follows: Consecutive posts merged no amit . log on http://en.wikipedia.org/wiki/Nuclear_decay
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may be i am asking the foolish ques. but these ques. is really disturbing my hypothalamus . we are all familiar with nuclear reaction . the most familiar one is the one with uranium . it changes to thorium, radon , polonium , radium or.......... depending upon the type of decay either its alpha, beta or any other . now if we take not elemental uranium but its oxide which is widespread then how stiochiometry will be maintained i.e there may be formation of oxides of thorium, radon , polonium , radium or.......... , but from where oxygen comes ????????????:confused::confused::confused::confused::confused::confused::confused::confused::confused:
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you are creating confusion in between two terms :- solvolysis and reaction as they differ a bit . and if i am not wrong then the competing reaction is elimination reaction just because of tertiary carbon . i have one problem which is blundering my CNS . when an alkyl halide is added to alc.KOH , there is an alkene formation. Alcohol is there but no ether formation takes place . how ? why ?
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What is ABS ?
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what you wanna say about this ? 1s - 1 2s - 2 2p - 3 3s - 3 3p - 4 4s - 4 3d - 5 4p - 5 5s - 5 4d - 6 5p - 6 6s - 6 4f - 7 5d - 7 6p - 7 7s - 7 6d - 8 now we are got same n+l values for some orbitals , which is going to filled first ? so i feel Aufbau is the most general one .
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me and my friend amit performed this exp. in same lab . now we are trying to relate these abnormal color shift with CFSE (crystal field stablisation energy ) . we noticed that color shifted from high wavelength to low wavelength region i.e. with passage of time energy required to excite electron from low energy level to high energy level decreases . these will only happen if any other chemical species (may me O2 or any other ) attack on complex or the extent of bonding b/n Ni and DMG decreases . BUT THESE IS COMPLETELY AN APPARENT GUESS . waiting for comments .........
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can you please write in short what actually you want ?
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i think it is not because of acidic nature of FeCl3 because i added to drop of dil. HCl to 5 drops of blood and i hadn't observed any change .