stopandthink

I see now. thaks

How do i find the square root of a negative number....? Lets say [math] \sqrt -4 [/math] My calculator gives me the answer 0 is it because [math] -a(-a)=+b [/math] where a equals -2(i assume -2 should be its squared root but its not)

Great that cleared up what i was having difficulty with. Thank you!

I didn't know you could apply [math]\frac{d}{dx} ax^n = anx^{n - 1}[/math] To [math](x-2)[/math] or [math](x+4)[/math] ______ Like this (x-2)^1 = 1*(x-2) is that what you did?

Of course. I got everything up to this point [math]1 \cdot (x + 4) + 1 \cdot (x - 2) = (x + 4) + (x - 2) = 2x + 2[/math] 1*(x+4)+1*(x-2) Where in the formula does it say to multiply by a one. I'm not that far into calculus to understand these type of functions yet, but i will. ------- it basically left me hanging after "And since we can find the derivative of things like (x - 2" after that im lost

I'm reading the intro to calculus on the forum and i'm confused... Basically it states [math]f(x) = (x - 2)(x + 4)[/math] and to find it's derivative you basically have to add the product rule formula, but i got completely lost at the last step,which is is where i need help at, and by the way would it not have been easier just multiplying the function at the very start... I mean i see that in the last step all that was done was just flipping it and then multiplying..

Lol! i see what i did wrong, Ignore this post! Thanks. Thank you! i was stuck trying to work it out some other way... Lesson learned.

I can't figure out how (1+h)^2 -1 = 1 + 2h+ h^2-1 my answer is 2+ 2h^2-1 Of course, my answer is incorrect but i cant see where it is i'm making a mistake.

[math]\frac{(1+h)^2 - 1}{h} = \frac{1 + 2h + h^2 - 1}{h} = \frac{2h + h^2}{h} = \frac{h(2 + h)}{h} = 2 + h[/math] I'm currently using one of the forums tutorial on calculus... And i'm stuck with a problem. The problem is i know it works out because iv'e substituted "h" with an actual integer, and my dilemma is i can't figure out how it went from, [math]\frac{(1+h)^2 - 1}{h} = \frac{1 + 2h + h^2 - 1}{h}[/math] Ignore the /font font=monospace thing, can't figure out how to remove it

Because one sees the other guy's face dirty and supposes his is also, but the other guy sees the clean face and assumes his face is also clean... i haven't looked at the comments so im sorry if this has already been answered.