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Bart

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Posts posted by Bart

  1. Updated VETER program, to verify the special theory of relativity is available on the link: url removed

     

    VETER program allows for a little different look at the theory of relativity, which can be helpful in the proper meaning of some of the phenomena described by this theory.

  2. I do not understand why the thread "VETER- The program for verification the special theory of relativity …." was closed by Mr Imatfaal along with the removal of the link to this program without any objections to its content.

     

    VETER is a simple, interactive computer program (in Excel), which in a clear math way present contradictions occurring in the special theory of relativity.

     

    In the first part of the program are presented unexpected, glaring inconsistencies occurring in the calculations, based on the basic formulas of special relativity, which definitely puts into questions the credibility of these formulas.

     

    In the second part of the program is mathematically demonstrated error in the original assumptions of the special theory of relativity. This error is based on a false interpretation of the results of experiments conducted by the Michelson-Morley and others, under which Einstein developed his theory of relativity.

    Calculations presented in the program unquestionably show that zero or almost zero shift of interference fringes, achieved in the experiments of Michelson-Morley and others, result from the Doppler effect, and it has no connection with the constant speed of light and controversial FitzGerald-Lorentz contraction of longitudinal arm of the interferometer, as it has been applied in the special theory of relativity.

     

    In the third part of the program is shown a simple example of conflict theory of relativity with the Doppler effect.

     

    The program is complemented by a mathematical evidence of wrong interpretation of time dilation, given on link: http://dl.dropbox.com/u/26262175/TimeDilationIsFalseProof.pdf

     

    Does anything presented in the calculations of the program VETER is incorrect or untrue?

    Let’s check it together.

     

    For the record I give once again the link to the program :

    http://dl.dropbox.com/u/26262175/VerificationTheoryRelativity.xlsx

     

    Regards,

  3. Sensei - I have just finished doing exactly the same calculations. I am very happy that I have the same answers as you

     

    attachicon.gifcalc sheet.jpg

     

    Explanation and some questions:

    1. The GPS system has been introduced for commercial use in the 90s, hence in my calculation was use value of G such that applied to 2002.
    2. Orbits of GPS satellites are strongly close to circular, so the average radius of the orbit 26 571 000 m is required in order to obtain an average orbital speed of the satellite 3 873.2 m/s. Such a speed is required in order to provide the GPS satellite orbital period equal to half of sidereal day i.e.11h58m2s .
    3. Adopted for calculation the radius of the Earth was as at the equator , because on the equator GPS also needs to work properly.
    4. Even the gravitational deviation of 45 721.203ns , as by your actual calculations, still does not ensure compliance with the detuning frequency used in satellites (45 721.203 – 7 210.7824 = 38 510.4206ns).
    5. Satellite orbits are inclined at an angle of 55 degrees to the equator. The Earth rotates at a speed of 463.8 m/s at the equator and 0 m/s at the poles. The question then arises of what the actual speed of the satellite is in relation to GPS receivers, anywhere on the Earth? How does this apply to the calculation of time dilation?
    6. Apart from the refraction of radio waves in the stratosphere and the troposphere of the Earth, the GPS receiver can see moving satellites at different and changing angles, so there is inevitably the Doppler effect, which changes the frequency of the received radio signals from the satellite.
    7. It should be noted that the GPS receiver does not have its own time, as the time in the GPS receiver is digitally synchronized with the satellite clock. There is no room, therefore, for any time dilation between satellite and GPS reciver, because the numerical values transmitted from the satellites do not change.
  4. Cite your source(s) for the values you've presented. Where do you get e.g. 45629.9702 ns?

    The calculation of the above values can be checked on the basis of formulas:

    Gravitational time dilation in the orbit Delta t1 = to / (1-2GM / (Rsat * c ^ 2)) ^ 0.5

    Gravitational time dilation on the surface of the Earth Delta t2 = to / (1-2GM / (R * c ^ 2)) ^ 0.5

    Daily gravitational time dilation of satellites = (Delta t2 - Delta t1) * 24 * 3600 * 10 ^ 9 ns

     

    where:

     

    Earth's mass M = 5.97 E+24 kg

    G = 6.6726 E-11 m3/kgs ^ 2

    The radius of the Earth R = 6 378 000 m

    The average radius of the orbit Rsat = 26 571 000 m

    The average speed of the satellite Vsat = 3 873.2 m / s

    to = 1 second

  5. The relativity bit comes from the fact that the GPS Satellites have an atomic clock on board - this enables the timings to be good and the receivers to make an accurate trigonometrical calculation of its separation from a number of satellites and thus its position on the earth. However it was predicted in relativity that clocks in frames with a relative velocity will be seen from the observers rest frame as running slowly. It is also predicted by general relativity that clocks at a higher gravitational potential will run faster.

     

    If we just ignored these predictions from relativity our GPS would not work - even the most accurate system would give incorrect answers. So we must adjust for two influences of the fact that the satellite is both in relative velocity with respect to the GPS receiver, and is at a higher gravitational potential. Special Relativity tells us, through simple sums, that the clocks on the GPS-Sats will run slower than earth bound by 7200 nano-seconds per day due to relative velocity . General Relativity tells us that the clocks on the GPS-Sats will run faster than earth bound by 45,900 nano-seconds per day. The net result is that we need to correct by 38,700 nano-seconds per day. We do this and the system works.

     

    This is what we mean by saying that GPS provides evidence to support relativity.

    In the GPS satellites detuning frequency of the signal generators is 10 229 999.99543 Hz, while the frequency of such generators in ground receivers is equal 10 230 000.00000 Hz.

    From this it follows that the detuning of generators frequency, gives the time deviation equal 38597.0653 nanoseconds / day.

    This is not consistent with the theory of relativity, as the required sum of relativistic deviations, resulting from the velocity of satellites and gravity, should be only 38419.1878 nanoseconds / day ( 45629.9702-7210.7824).

    As you see the difference to the relativity requirements is significant.

  6. Simple computer program that enables a quick and easy verification of the theory of relativity is available on the link: http://dl.dropbox.com/u/26262175/VerificationTheoryRelativity.xlsx

    The program calculates the delay of the clocks in motion for any speed of timing pulses in these clocks.

    Very interesting results of the calculations are obtained for example for the pulse rate: 10 m/s, 250 000 000 m/s, 290 000 000 m/s and higher.

  7. Updated paper on the holes in the SR theory is available on the link given in the closed thread: "Clocks do not confirm relativity".

     

    Please do not run away from attempts to clarify, if it is possible, troublesome threads.

     

    Instead of sweeping it under the carpet, sooner or later the physicists will have to take their position on the holes in the theory of relativity, shown in the above mentioned paper.

  8. Version of the article in my opennig post was a bit of my provocation to ignite a professional discussion on the presented example. Unfortunately provocation was unsuccessful. In fact, only Mr. Janus tried to explaina little but not quite.

     

    So now on the link as in post #1: http://dl.dropbox.com/u/26262175/ClocksNotConfirmRelativity.pdf is placed the right article on the subject, at 1 and 1/2 pages plus tables and figures. Total 4 pages.

     

    Extended article presents a further example of unreliability of SR theory.

     

    Once some of the famous physics said somthing like this: "If you can not explain to the bartender a given theory, it means that you yourself do not undertstand the theory, or the theory is just a fairy tale."

     

    I admit that I still do not understand the theory of relativity. smile.png

     

    Bart (ender)

  9. It's shorthand for exponential notation. Thus 1.11e-6c = 1.11x10^-6c = 0.00000111c, which is the speed of sound as expressed as a fraction of the speed of light.

     

    The general formula is

    [math] S = \frac{u+v}{1+\frac{uv}{c^2}}[/math]

     

    In this case u is the speed of the ship relative to A and B, and u is the speed of the sound clock pulse as measured in the ship

    S is the speed of the same pulse relative to A and B as measured by A and B.

     

     

    You can do yourself. Take the equation I gave for the orthogonal velocity addition. Plug in 0.866 for v and 0.00000111 for u (warning: you will need to use something that will carry out to quite a few decimal points)

    Once you get an answer, then plug S into:

     

    [math] \sqrt{S^2-0.866^2}[/math]

     

    Which gives you the tranverse component of the sound pulse crossing the ship according to A and B. You will get an answer of 0.000000555, or half the speed as measured by someone in the ship. Since the tranverse width of the ship is the same in both frames, the pulse will take twice as long to make the round trip according to A and B, than it does for someone in the ship.

     

     

    I have already spent more time on this than it deserves. I will simply repeat what I know that I have told you before and Swansont has already alluded to in this thread. SR is mathematically and logically consistant. If it wasn't, it would have been tossed in the trash bin a long time ago. It is impossible to come up with any situation, scenario or thought experiment that, if SR is properly applied, will result in a contradiction or flaw in SR.

     

    The only way to expose a problem with SR is to provide real experimental results from an actually physically performed experiment that gives results that disagree with what SR predicts or provide a real-life observation of a natural event that disagrees with SR.

     

    Otherwise, you are just wasting your and everyone else's time.

    Thank you very much for your reply, but to dispel my doubts, please confirm what ticks of sound clock in seconds will see observer A, according to the theory of relativity at speed of the ship 260 000 km / s? And what ticks period should see the observer B?

     

    I'm sorry, but I must repeat yet my second request for the professional explanations, if it is possible, what ticks of the radio clock (pulsar) should see passenger in the ship and each of stationary observers A and B.

     

    I believe that the time spent on the search for truth is not a waste of time!

  10.  

     

    He does so, because he thinks he can simply take the distances traveled reative to the ship and divide them by the speed of sound. But this isn't what SR say you have to do. SR says you have to apply the relativistic formula for the addition of velocities to get the speed at which the sound travels with respect to the ship in each direction according to A and B. Thus, in forward direction the sound travels at:

     

    [math] \frac{0.866c+1.11e-6c}{1+\frac{0.886c(1.11e-6c}{c^2}}- 0.866c = ~2.78e-6c = 0.0832646 km/s. [/math]

     

    If L' = 0.08325 km, then the trip time for the forward leg is ~1 sec.

     

    For the return trip, we get a speed of

     

    [math] \frac{0.866c-1.11e-6c}{1-\frac{0.886c(1.11e-6c}{c^2}}- 0.866c = 0.0832647 km/s. [/math]

     

    Which gives a return trip time of ~1 sec

     

    The total round trip take 2 sec. Which matches the result of the light clock.

     

    In the case of the tranverse trip, you have to apply the formula for orthogonal velocities.

     

    [math]S= \sqrt{v^2+u^2-v^2u^2}[/math]

     

    to work out the speed at which the sound travels with respect to the ship according to A and B as predicted by SR.

    And if you do so you get the same agreement with the light clock.

     

     

     

    Your explanation for forvard and return is not clear to me. Could you give the full physical formula for your expression please.

    What is the parameter e?

     

    For transverse direction:

    Can you prove it by calculation by above formula and show us the value of the sound speed and the ticks period for transverse trip?

    For radio clock:

    Can you show your math formula and calculation of the ticks period for radio clock seen by observer A and by observer B?.

  11.  

    Updated version (v.4.0) of the program Sagitarius BR, to calculate the rotation of stars in spiral galaxies is available on the links:

    Program (8,7MB): http://dl.dropbox.com/u/26262175/SagitariusBRprogramForCalculationsOfSpeedOfStars.xlsx

    Description: http://dl.dropbox.com/u/26262175/SagitariusBRprogramDescription.pdf

     

    The calculations of the Sagitarius BR program, clearly show that the uniform speed of rotation of stars in galaxies, as well as higher than that required by classic calculations the speed of rotation of galaxies in clusters, are the result of natural distribution of matter in these objects and for their explanation, is not need an exotic dark matter.

     

    Below some question received from the Internet regarding this program, together with an explanation.

     

    Q: The observed rotation speeds of galaxies in galaxy clusters, which shapes are generally spatial and not flat like the shapes of galaxies, is higher than that calculated by the classical laws of gravity. How is this possible to explain that without the participation of dark matter, based solely on the calculations of the Sagitarius BR?

     

    A: Carried out by the program Sagitarius BR, calculations of the resultant gravity g = GM/R^2, produced jointly by all the stars scattered across the galaxy disc, shows always higher gravity, for any distance in the plane of the disk, than that required by classic calculations . The difference in the gravity, greatly depends on the diameter of the dispersion of stars (diameter of the galaxy disk) and increases with the increasing dispersion. This relationship is easy to check by every skeptic in the calculation of their own, on any simple model, without participation of the Sagitarius BR.

     

    In galaxy clusters, planes of the rotating galaxy discs, for each orbiting galaxies in the cluster (with any planes of their orbits), must lie in accordance with the laws of physics, in the planes of their orbits. The same gyroscopic effect is visible in the solar system, where the axes of rotation of the planets are arranged vertically to the plane of its orbit, with some variations resulting from the precession. Therefore the vectors of attractive forces of galaxies to the center of the cluster, always lie in the planes of rotation of the galaxy discs. As already explained, the gravity in the plane of galaxy disk is always greater than that required by the classical formula g = GM/R^2, for any distance from the disk center. Therefore, the observed rate of rotation of galaxies in clusters, will be greater than that calculated classic, which in 1933 was challenged by Fritz Zwitzky and to justify this discrepancy he introduced ad hoc the concept of dark matter, which exist to this day.

     

    There was another question from the internet which, together with an explanation is presented below:

     

    Q. On the chart presented in the program Sagitarius BR, there is increased speed ("hill") of rotation of the stars on the edge of the galaxy disk. How to explain it?

     

    A. "Hill", or "hills" in the graph occur only if the % difference of the modeled distribution of mass in the disk between successive circles is sufficiently large. At the differences of less than 1% "hills" are unnoticeable. In the case of circle #20, this is especially evident because the circle #21 and the next, have modeled mass of 0% and then may be more visualized the domination of gravity of the local equivalent star from the circle #20. It is possible to filter out that domination by the program, but deliberately it is not made, in order not to distort the image of the calculations.

  12. Updated version (v.4.0) of the program Sagitarius BR, to calculate the rotation of stars in spiral galaxies is available on the links:

    Program (8,7MB): http://dl.dropbox.com/u/26262175/SagitariusBRprogramForCalculationsOfSpeedOfStars.xlsx

    Description: http://dl.dropbox.com/u/26262175/SagitariusBRprogramDescription.pdf

     

    The calculations of the Sagitarius BR program, clearly show that the uniform speed of rotation of stars in galaxies, as well as higher than that required by classic calculations the speed of rotation of galaxies in clusters, are the result of natural distribution of matter in these objects and for their explanation, is not need an exotic dark matter.

     

    Below some question received from the Internet regarding this program, together with an explanation.

     

    Q: The observed rotation speeds of galaxies in galaxy clusters, which shapes are generally spatial and not flat like the shapes of galaxies, is higher than that calculated by the classical laws of gravity. How is this possible to explain that without the participation of dark matter, based solely on the calculations of the Sagitarius BR?

     

    A: Carried out by the program Sagitarius BR, calculations of the resultant gravity g = GM/R^2, produced jointly by all the stars scattered across the galaxy disc, shows always higher gravity, for any distance in the plane of the disk, than that required by classic calculations . The difference in the gravity, greatly depends on the diameter of the dispersion of stars (diameter of the galaxy disk) and increases with the increasing dispersion. This relationship is easy to check by every skeptic in the calculation of their own, on any simple model, without participation of the Sagitarius BR.

    In galaxy clusters, planes of the rotating galaxy discs, for each orbiting galaxies in the cluster (with any planes of their orbits), must lie in accordance with the laws of physics, in the planes of their orbits. The same gyroscopic effect is visible in the solar system, where the axes of rotation of the planets are arranged vertically to the plane of its orbit, with some variations resulting from the precession. Therefore the vectors of attractive forces of galaxies to the center of the cluster, always lie in the planes of rotation of the galaxy discs. As already explained, the gravity in the plane of galaxy disk is always greater than that required by the classical formula g = GM/R^2, for any distance from the disk center. Therefore, the observed rate of rotation of galaxies in clusters, will be greater than that calculated classic, which in 1933 was challenged by Fritz Zwitzky and to justify this discrepancy he introduced ad hoc the concept of dark matter, which exist to this day.

  13. Let's take standing at A:

     

    He sees the Ship leave at 0.866c. The Doppler shift ratio for this speed is ~0.268 (because ship A is receding). After 1000 sec by his clock Ship A and Ship B should meet. However, this meeting point is 866.6 light sec from the observer, so it will take an additional 866.6 sec before he sees the ships meet. Thus for 1866.6 sec he will see the the clock on Ship A tick at a rate of ~0.268, and therefore see ~500 sec accumulate on the Ship's clock between leaving A and meeting the other ship.

     

    B is 1333 light sec away, So he won't see the ship leave B until 1333 sec have passed on his clock. (He actually won't see the ship leave after the ships have met by his clock. Since ship B is approaching, once he sees it leave, he will see its clock Doppler shifted by a factor of ~1.66, Again, he'll see the ships meet when his clock reads 1866.6 sec. Thus he sees Ship B's clock Doppler shifted for ~533.6 sec and accumulate ~885 sec from the time it leaves B until the Ships leave.

     

    You can do the same thing with the observer at B and you will end up with the same final conclusion.

     

    It doesn't matter where you put the Observer, As long as you properly account for light propagation delay and Doppler shift, he will always see ship A and ship B accumulate the same amount of time as the ships themselves say they do.

    Because I was calculating Relativistic Doppler shift not time dilation. Time dilation is what you would get if you could make a side by side comparison between the clocks. Relativistic Doppler shift is what you actually observe. Relativistic Doppler shift takes into account not only time dilation but the change in light propagation delay due to the changing distance between observer and source.

     

     

     

    Oh yes, if in the classical Doppler effect, we introduce the formula of relativistic time, instead of the classical time, we obtain the formula for the relativistic Doppler effect and then everything is mathematically correct.

     

    Thank you very much for very clear explanation of this case.

     

     

     

  14. The outside observer sees the same reading on the ship's clocks when they meet as the observers in each ship see on their own clock.

    ........

     

    Thus the outside observer observers in both ships agree as to how much time elapses fro each ship between their starting their trip and the meeting of the ships.

     

     

    I do not understand it. How did you get it? The outside observer, due to the Doppler effect, would see the clocks in the rockets, different when standing at point A, different when standing at point B, and different when standing far away from the line of rocket movement.

     

     

    When the ship leaves point A he sees Ship B as it was 1333 sec ago. Upon reaching 0.866c, he sees events at B doppler shifted at a rate of ~3.73, so after ~357 sec by his own clock, he sees the ship leave B, and then sees the clock on ship B Doppler shifted by a factor of ~6.18 for ~143 sec. This means he sees Ship B's clock advance by ~885 sec from the time he sees the ship leave B to the time they meet.

     

     

    At a speed of 260 000 km/s for the ship A, the clocks on board, according to SR, will slow down by 2. So why you have 357sec ?

  15. An outside observer sees them meet after 1000. seconds. 4e8 km is 1333 light-seconds. A travels 866.6 light-seconds, while B travels 466.6 light-seconds

     

    2.6e5 km/s is .866c, a gamma of 2. A sees the travel distance of 433 light seconds, taking 500 seconds.

    1.4e5 km/s is .466c, a gamma of 1.13. B sees his travel distance as 413 light seconds, taking 885 seconds.

     

    Thanks for your reply, but I defined my question probably not quite clear .

     

    An outside observer will see 1000 seconds on his own clock. My question is what the observer will see on the clocks in rockets?

     

    According to SR, the rockets approaching each other with the resulting relativistic speed of 284 810 km / s . How does this apply to the clock displays in the rockets, and on the local time of their meeting?

     

     

     


  16. To dispel my some doubts of interpretation SR theory, could you please give a solution for the following example:

     

    Let the point A is far from B with L = 400 000 000 km. At the same time from point A and B, start 2 rockets to meet with each other. The rocket from the point A is moving at v1 = 260 000 km / s, the rocket from the point B is moving at v2 = 140 000 km / s.

    The question is:

     

    How many seconds, according to the theory of relativity, will elapse on the clocks in rockets, since the start until meeting:

    1. seen by the passengers in the rockets?

    2. seen by an observer at rest ?

     

    This is not a homework.



  17. You didn't exactly phrase your post in a way that, in conjunction with previous discussion, lends itself to explanation of your errors. It's pretty clear that you have decided that relativity is wrong, but it's equally clear that you don't understand and can't properly apply it. What's the incentive to correct you, when you are resistant to correction?

     

    The theory of relativity since its publication, is disputed by many outstanding physicists, among others, by genius Tesla, which had more than 1,200 patents, Einstein did not have any. From the announcement of the theory of relativity in 1905, was published a few thousand (!) scientific articles and books written by well-educated physicists, demonstrating the fallacy of this theory. Here, for example, only a few titles in recent years..

     

    1. Arteha S.N., Critical Remarks to the Relativity Theory, Spacetime & Substance 2005, v. 6, № 1 (26), pp. 14-20.
    2. Brinkmann, Karl: Grundfehler der Relativitätstheorie, © 1988, ISBN 3-89180-019-3, Hohenrain Verlag GmbH, 280 Seiten.
    3. Essen, Louis 1971: The Special Theory of Relativity: a critical analysis / L. Essen. - Oxford: Clarendon Pr. 1971. 27 S.
    4. Galeczki, Georg: Requiem für die Spezielle Relativität, / Georg Galeczki, Peter Marquardt. - Frankfurt a. M.: Haag u. Herchen, 1997, 271 S.
    5. Gulati, Paul S.: Big howler, Einstein’s Theory of special relativity. 1982.
    6. Relativity, time, and reality: a critical investigation of the Einstein Theory of Relativity from a logical point of view / by Harald Nordenson. -London: Allen and Unwin 1969. 214 S.
    7. Parish, Leonard 1977, The logical flaws of Einstein's relativity / by Leonard Parish. - Luton: Cortney Publications 1977. 171 S
    8. Rebigsol, Cameron Y.: Mathematical invalidity of relativity. 1996
    9. Sekerin, Vladimir Ilich: The relativity theory - the mystification of the century 1991.
    10. Tipnis, Sharad D.: Einstein’s relativity the greatest fallacy in the twentieth century, 1985
    11. AAAS, Pacific Division. Meeting, San Francisco 1994. Proceedings.. Xu, Shaozhi: Two conclusive proofs of variation of light velocity.
    12. Galilean electrodynamics. 9. 1998, Nr. 2, S. 23-27. Agathangelidis, Antonis: Experimental disproof of special relativity theory.
    13. Barth, Gotthard: Der gigantische Betrug mit Einstein, historisch und mathematisch, © 1987, 92 Seiten
  18. When you do the analysis wrong, or apply the wrong analysis, you'll get the wrong answer. Big surprise.

     

     

    Your answers did not explain or a bit of my doubts and as you wrote, error of my thinking. But thank you very, very much for discussion and a possible further discussion in this thread I leave to others.

     

     

     

     

  19. ....

     

    Since you refuse to include in your scenario a way to make any other comparison, you really can't draw any further conclusions.

     

    So, let's check for our example, all possible variants of the comparison of the pulsar pulses and clocks on the spaceship, in relation to the clocks on the Earth. Gamma is 2.

     

    1. According to the SR, clocks on the spaceship slowdown 2 times, but let in spite of the SR, the transverse Doppler effect for 1PPS pulse does not exist.

     

    Captain of the spaceship will see 2 pulses from the pulsar every 1 second. Such information for the observer on Earth will indicate that the clocks in the spaceship actually slowed down 2 times (but without existence of the transverse Doppler effect).

     

    2. Clocks on the spaceship slowdown 2 times, but there is also the transverse Doppler effect (as it SR says), which increases the length of the pulsar pulses also 2 times.

     

    Captain of the spaceship will see then 1 pulse from the pulsar every 1 second. Such information for the observer on Earth will indicate that the clocks in the spaceship run in fact, exactly as the clocks on Earth. This is so, in spite of the slowing down of clocks in the spaceship, because duration of the outer events as seen from the spaceship, also slowed down there 2 times.

     

    3. Clocks on the spaceship run at the same rate as on Earth, but there is also the transverse Doppler effect, which increases the length of the pulsar pulses 2 times.

     

    Captain of the spaceship will see then 1 pulse from the pulsar every 2 seconds. Such information for the observer on Earth, taking into account the existence of the transverse Doppler effect, will indicate that clocks on the spaceship run in fact, exactly as the clocks on Earth. This is so, in spite of the slowing down of clocks on the spaceship, because duration of the outer events as seen from the ship, also slowed down there 2 times. Without taking into account the transverse Doppler effect, the observer on Earth will state that clocks on the spaceship run two times faster than on Earth.

     

    4. Clocks on the spaceship run at the same rate as on Earth, and the transverse Doppler effect for 1PPS pulse does not exist.

     

    Captain of the spaceship will see then 1 pulse every 1 second. Such information for the observer on Earth will indicate that clocks on the spaceship run exactly as the clocks on Earth.

     

     

    So, we have analyzed all four possible variants of the comparison, and as can be seen here, each of these variants contradicts the theory of relativity. (?)

     

  20. That's a different question. You asked what the spaceship sees, not what an observer on Earth sees. The Earth observer was not part of the question at all. Earth sees the spaceship's clock running slow.

     

     

     

    That the spaceship sees 1 pulse every two seconds.

     

     

    An observer on the Earth does not have any possibilities of observing clocks in the spaceship.

     

    Information about what is happening in the spaceship I can receive only from you, through Spacenet communication system. You sent me a message that 1 pulse from the 1PPS pulsar has a period of 2 seconds. This is a clear indication to me, that according to this information, the clocks in the spaceship speed up twice, when compared to the clocks on Earth.

     

    The theory of relativity is based solely on the transport side of the light, completely ignoring the most important information layer in this medium, what is a big drawback to this theory.

     

     

     

  21. Gamma is 2, so 1 pulse every 2 seconds.

     

    .

     

    If it be so, that 1 pulse from the 1PPS pulsar will have a period of 2 seconds in the spaceship, it would mean that the clocks in the spaceship not slowed down, but speed up twice, compared to the clocks on Earth.

     

     

    "Since the travel to XXL is 1 LY in the rest frame of the earth, in the spaceship traveling at 0.866c it's 1/2 LY, so it takes .433 year in the spaceship frame while on earth they measure .866 years."

     

    I do not understand it. Could you explain what you want to show, here?

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