rakuenso

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Posts posted by rakuenso


eh? I've done calc II and we went over quite a bit of vector calculus. But all the stuff we did dealt with flows, and integrals of dot products (which is just a scalar), and stuff like stoke's theorem. here it seems like I'm integrating an actual vector as opposed to a dot product. So the problem is analagous to finding the integral curves for a vector field (which here is the gradient) using ODEs?
nm I think I get what you mean now, if my vector field is [math]< \frac{\partial V}{\partial x}, \frac{\partial V}{\partial y} >[/math], say [math]V=\frac{1}{xy} [/math] then I would form the autonomous system, as it is independent of time:
[math] \frac{dx}{dt} = \frac{\partial V}{\partial x} = \frac{1}{xy(xy)} [/math]
[math] \frac{dy}{dt} = \frac{\partial V}{\partial y} = \frac{1}{xy(xy)} [/math]
so I would have to look for an integral curve with components (x(t), y(t)) that obeys the above equations
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Are [math]x^A[/math] my variables? like [math]x=x^1,y=x^2[/math] etc. And what erxactly is [math]X^A[/math]?
How do you arbitrarily parametrize [math]x^A[/math] wrt to t? Or is this [math]x^A(t)[/math] exactly what I'm trying to solve?
I also have difficulties seeing where the integration along a "vector" part comes in.
For two dimensions, so far I've written the [math]n[/math] th point [math](x_n, y_n)[/math] as the following, over some interval tiny interval [math]t[/math] (in the case of the unit vector it is equal to the magnitude of the vector)":
[math] x_n = x_0 + \frac{1}{t} [\frac{\partial f}{\partial x}(x_0,y_0) + \frac{\partial f}{\partial x}(x_1,y_1) + ... + \frac{\partial f}{\partial x}(x_n,y_n) ] [/math]
[math] y_n = y_0 + \frac{1}{t} [\frac{\partial f}{\partial y}(x_0,y_0) + \frac{\partial f}{\partial y}(x_1,y_1) + ... + \frac{\partial f}{\partial y}(x_n,y_n) ] [/math]
note that [math](x_1,y_1), (x_2,y_2) .. etc [/math] can be found using the above definition
The path then would be comprised of the points [math] (x_0,y_0), (x_1,y_1) ... (x_n, y_n) [/math], which when taken over the [math]\displaystyle\lim_{n\to\infty}\displaystyle\lim_{t\to\infty}[/math] becomes continuous and never ending. Surely, given some function [math] f(x,y) [/math] this path can be traced out using numerical methods, but a method of finding an analytic solution seems much more difficult.
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Suppose I have a function [math]f(x,y)[/math], along with a gradient at some arbitrary point [math](x_0, y_0)[/math]
The surface is smooth and [math]C^1[/math], there thus also exists some gradient vector:
[math]<\frac{df}{dx}(x_0, y_0) , \frac{df}{dy}(x_0, y_0)>[/math] I want to "follow" this vector to the next point [math](x_1, y_1)[/math], here there is another gradient vector [math]<\frac{df}{dx}(x_1, y_1) , \frac{df}{dy}(x_1, y_1)>[/math], I repeat this process for up to [math](x_n, y_n)[/math].
How do I write an expression for the curve? It seems like I would have to integrate along a vector somehow?
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Bignose, under what conditions is
[math]\frac{d}{dt}\frac{dx}{dx}=\frac{d}{dx}\frac{dx}{dt}[/math]?
I tried to do some examples, say:
[math] x = t^2 [/math]
[math] \frac{dx}{dt} = 2t [/math] [math]\Rightarrow[/math] [math] \frac{d}{dx}\frac{dx}{dt} = \frac{1}{\sqrt{x}}[/math] since [math] \sqrt{x}=t [/math]
However,
[math] \frac{d}{dt}\frac{dx}{dx} = 0 [/math]
So [math] \frac{d}{dt}\frac{dx}{dx}\neq \frac{d}{dx}\frac{dx}{dt} [/math]
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Hi I have a function f:
[math]f(x(t))=\frac{d(x(t))}{dt}+x(t)[/math]
Now how would I differentiate f with respect to x
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Hmm by  i meant the absolute value, not the norm. Are they equivalent?
Merged post follows:
Consecutive posts mergedHmm by  i meant the absolute value, not the norm. Are they equivalent?Because in this case, my norm/length is defined as exactly:
[math] x = \int_\gamma f(s) ds [/math] where x is a vector connecting two points..
edit: ajb, I think I'm starting to see what you mean =)
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Ｉ thought the space becomes a metric space whenever you arbitrarily define a function d that satisfies the axioms:
1. d(x, y) ≥ 0 (nonnegativity)
2. d(x, y) = 0 if and only if x = y (identity of indiscernibles)
3. d(x, y) = d(y, x) (symmetry)
4. d(x, z) ≤ d(x, y) + d(y, z) (triangle inequality).
My definition above seems to satisfy all 4.
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You don't need a metric to define line integrals, you need a onedimensional volume or a oneform. You need an invariant notion of integration.
So, let us take [math]\omega_{U} = \omega_{A}(x)dx^{A}[/math] with [math]U \subset M[/math] with local coordinates [math]\{x^{A}\}[/math] and [math]\gamma :[a,b] \rightarrow U[/math] where I will use the notation [math]\gamma^{*}x^{A} = x^{A}(s)[/math] where [math]s[/math] is the coordinate on the interval. Then
[math]\int_{\gamma} \omega := \int_{a}^{b}\left( \omega_{A}(x(s))\frac{dx^{A}(s)}{ds} \right)ds. [/math]
In practice you may need more than one coordinate patch. The integral is also independent of how you pick the coordinate patch(s). Note no metrics.
You will need a metric if you want to have a notion of distance. In your original post I am not sure what f is or what norm you are using. Norms and metric are just about the same things in this context.
I wanted to define the metric function [math]d(A,B)[/math] using the aforementioned line integral but I was afraid of a circular argument like Killjoy said. For simplicity we can say f is the potential energy V, which is only dependent solely on some point in the configuration (Q) manifold. (Eventually I will redefine f on QP space as TV)
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Hi,
Suppose I have two points A, and B in some Ndimensional manifold.
I would like to define distance (or metric) between A and B as follows:
[math]d(A,B)=min  \int_\gamma f(s) ds  [/math] along some curve [math]\gamma[/math]
In my head, it seems to be possible to evaluate a line integral without precisely defining distance. (ie. we just take tiny little points along this line, and evaluate f(s) at each tiny little point).
However, all equations I've seen uses something like:
[math]ds=\sqrt{{dx}^2+{dy^2}}[/math] which seems like a euclidean metric.
So here are my ultimate questions, 1) is it possible to evaluate such a line integral without defining a metric, and 2) would make it sense to define such a line integral
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Is there a name for a family of parametric curves [math] x(t) , y(t) [/math]where...
[math](\frac{dx}{dt})^2+(\frac{dy}{dt})^2=1[/math]?
If possible, generalized to multiple dimensions...
[math](\frac{dx_1}{dt})^2+(\frac{dx_1}{dt})^2+...+(\frac{dx_n}{dt})^2=1[/math]
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nm just got your message, QTPH looks like a 6N+2 dimensional space
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Well, I'm thinking of surfaces of only potential energy, and yes, I am precisely trying to find the metric the metric configuration space (or if doesn't come predefined with one, find something analagous)
If I understand correctly (from what I've read about tensor calculus in a night)
If we let the set [math]\left\{x^1,x^2,...,x^N\right\}[/math] as a point that represents a certain configuration, with [math]x^1,x^2,...,x^N[/math] variables themselves being the coordinates in configuration space
a path (or curve) in configuration space can represented as:
[math]x^r=f^r(t)[/math] where [math] r=(1,2,...N) [/math]
if we add the dimensionality of energy, ie, we form the energyconfiguration space, which is an N+1 dimension space, then a point in energyconfiguration space becomes the set [math]\left\{x^1,x^2,...,x^N,x^z\right\} \; where \; x^z[/math] is the newly added dimension
Q #1: Is an energy surface Z represented in this energyconfiguration space, [math]u^i[/math] some parameter, written as:
[math]x^s=f^s(u^1,u^2,...u^r)[/math] where [math] r=(1,2,...N) \; \; and \; \; s=(1,2,....N,z) [/math] ?
eventually we'd be able to eliminate the parameters and write [math] x^z = g(x^1,x^2,...,x^N) [/math], forming a surface. What would these parameters [math]u^i[/math] be?
Q #2: how would you represent the curve in the energyconfiguration space bound to the surface Z?
Would it be [math] x^s=f^s(t) [/math] where [math] s=(1,2,....N,z) [/math] still? this seems like the unbounded form, ie, there's nothing to say it has to be on the surface? How would I express it in a general form, but require it to be on the surface?
I'm planning to add two more dimensions to this energyconfiguration space later
EDIT: Is it possible to find the "length" of a line connecting two points in space without defining the metric?
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Ah, thanks.
Unfortunately it doesnt look very euclidean at this point. I suppose physically x1,x2..xn represents a certain configuration of a system, and Z is the energy of that configuration.
So the difference between x1,x2,...,xn and y1,y2....yn would be physically interpreted as the change in the configuration. While the difference in z0=z(x1,x2,...,xn) and z1=z(y1,y2...yn) would be the difference in energies of the configurations. The surface thus doesn't seem Euclidean
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Thanks for the book advice, I haven't quite figured out what the metric space is yet, so I'm leaving it pretty generally. I'll probably be working on some connected Riemmann manifold
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I have a surface Z, which is a function of the variables x1,x2,x3... etc. ie. Z(x1,x2,x3...) I have a point Z0 and a point Z1 which corresponds to some point on this surface. There is some line M that connects Z0 and Z1 on the Z surface, note that M does NOT have to be the shortest distance. However, M must be bound to the surface Z.
How do I find the length of the line M on this surface? Ideally the expression would be somehow linked to the directional derivative,
IE. I've been thinking of slicing the line M into tiny little components, and taking the directional directive at each point of M, the integrating with respect to.. something (maybe dx1, dx2, dx3...
Any tips? Some recommend arc length, others recommended differential manifolds (Which I have NO IDEA)
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Hi guys,
I was wondering about the feasibility of combining two domains from different proteins together. What sort of results can i expect? How often would I end up with a fully functioning protein?
I'm thinking about giving a nonspecific enzyme with a domain that allows endonucleases that cut specifically
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Hi guys...
I was wondering if the change in entropy (ΔS) is a state function? I know that S is a state function because its dependent only on S=k * ln W
but in class we learned that
ΔS_total_irreversible_process > 0
and
ΔS_total_reversible_process = 0
wouldn't this mean that delta S is a process dependent nonstate function?
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What are your opinions on germline gene therapy if it becomes a feasible reality?
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Man... I just got all 4 taken put, without being put to sleep.
Damn.
So my Q is: why the hell do we have them anyways? I woulda thought they were a negative trait to have (Since it crunches your teeth)...
oy
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There's a lot of debate about whether or not viruses are alive' date=' I know, which is why I chose it for my research paper. There still isn't a lot of good information out there, most is just personal opinion. I spent all evening in different libraries doing research but it seems most scientists havn't published much about it. There are good articles about the connections viruses have with living things (the development of the nucleus, etc), the history of viruses, and how they operate, but not much about whether they're alive.
I guess my conclusion will be that even if viruses are not alive, they still share a vital connection with other living creatures.[/quote']
there's also been 60931802681 threads in the past about this.
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Would be nice =D
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The list in my physics book reads 0.510 998 918 MeV/c^2
my Q is: how the hell do you measure something to 0.000 000 001 degree of accuracy? not to mention its in MeV/c^2 to start with!
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agreed with guy above ^^
i think a bomb calorimeter would be most suitable
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experimental visualization of hydrogen atom densities
in Quantum Theory
Posted
Has anyone experimentally obtained a picture like this:
http://en.wikipedia.org/wiki/File:HAtomOrbitals.png
If so, where? If not, how do we actually know it's correct?