Pre4edgc

I'm not good either... 4902... That's difficult...

Done in five minutes: [hide]The evil llamas will eventually take over the planet earth.[/hide] Pretty good. A few spelling errors though.

Well, it's not substitution. That's obvious with "ealaee e", since neither "a" nor "i" can be substituted and still create a real word with "ealaee", so I'll say it's transposition. Lemme get started.

....Ok... umm, about my code... I lost the key. Can't find that stupid sheet of paper. But I kind of have to thank myself that I still have a copy of some of my longer encryptions, and remember the encryption technique, so I have to solve my OWN codes... Kind of embarrassing... But don't worry. I'll rebuild it.

Well, about my original hypothesis... It isn't right... I tested it with some other amounts, and it didn't seem to work. I can't get a formula to determine the number of times it can take to get back to square one with any given amount, but like abskebabs, I realize the number of times it takes may be related to the multiple of the differences between A and B. I don't think a formula for this is possible, but perhaps a shortcut through that process. I'll keep some updates while I continue looking through this.

Well, from what I see with both of your examples (10 and 7, 8 and 5) They are both seperated by three, which would mean that in order to get a certain amount, they would end up with a multiple of three in both containers. ie Eight goes into five. Three in eight, five in five. Empty five. Pour three into five. Fill eight. Pour two into five. Six in eight, five in five. Both end up with multiples of the difference. So would that mean the same if you had ten and six instead of ten and seven? I think that the amounts you can get are directly restricted to the multiples of the difference of the two amounts... In my opinion at least. Okay. TIme for an update. Yeah, maybe it's been just ten minutes, but I may have found a formula that tells the number of times you can pour before you get the amount maxed by B in A. I repeated it, and it worked just fine. I had it where (A-B)^2=B. I tested it with a slightly different equation rather than the 10 and 7. I turned it to 10 and 6. And it still worked! I worked it out, and after a repeated 16 steps for that last one, it turned out that you'd get 6 pints in the 10 pint container, thus causing a repeat in the pattern. It works for the 10 and 7 one as well. I mainly had it to where the amount in the 10 container changed each time to an amount less than ten after it filled the other container. Like when ten filled 7, leaving 3 in it. That I said was step 1. Then when you emptied 7, filled it with the three, refilled the ten, and dumped four into the seven, and left 6 in the ten, it became step 2. I haven't worked a way to get an exact answer of steps to get a particular number, seeing as the ten and six one only has four different amounts...

I do. It was pretty interesting, and gave me something to do on days I was bored.

Expansion by diagonals work well too. 10 -10 0 0 -10 17 -2 -5 0 -2 7 -1 0 -5 -1 26 (Sorry, don't know how to write the math like you did.) Expand it like this. Take the first three rows, copy them, and put them at the end like this: 10 -10 0 0 10 -10 0 -10 17 -2 -5 -10 17 -2 0 -2 7 -1 0 -2 7 0 -5 -1 26 0 -5 -1 Then take the downward diagonals, first to last, and then the upward, and multiply the numbers in those diagonals. Kind of a big number, but it still works. In this case, a downward would be 10, 17, 7, and 26. Multiply them, and keep record of the number. After you do that for all of them, add the products from the downward diagonals, and subtract the products of the upward diagonals. Your determinant is that. Not very mathy, and I had to look up some of it in my math textbook, but it should work.

Well, the y=mx+b is the formula for a line in a 2-axis graph. I'm not sure what the formula for the 3-axis graph is, but like Dave said, they're just like 2d. Just follow the x, y, and z axis to plot a point (On paper) like you would with just x and y. And make sure that if it was supposed to be rectangular that it doesn't end up triangular... That sucks.

Ok. It starts like this: Any planet that has any capable release of CO2 will release it. But after just so long, in any atmosphere, it will continue to grow until that planet is full to bursting, and then it does, bursting a hole through the atmosphere and destroying everything on the planet until it's desolate. See what I'm getting at? Our planet has been alive for 4.55 billion years, and for about half of that, or less, life has created CO2. But since we have grown, and destroyed things that reduce it, including the exponential amount of exhaust that we release. Because of this, then the CO2 will reach this critical point, and rupturing the atmosphere, and this is what I believe to be the end of what we call Global Warming. We will all die in this ending. To clarify on the rupture of the atmosphere, the CO2 that will fill, as it does now, will absorb the sunlight and pollution, weakening it, and create a small rupture. It will grow, because we see that some CO2 is lessening, and we think we are on the decline that we believe to happen every couple thousand years (as explained in Al Gore's movie). But instead of lessening, it continues to leave and create a bigger hole, until the UV rays from the sun burns us to a crisp, as well as the rest of the life, and that's it. We're gone. In addition, this would happen to any other planet that would have the same conditions. And the thing is, with any life, this would happen, and would therefore be a natural condition. It would be part of life, and would also explain why we can't find any other life, if it exists. If you can find a flaw or something in the theory or help clarify it, then I would be very grateful.

Nice call.

Well, graphing calculators have functions built into them that you just fill in. Also, it has a y= section (I have that kind: TI-82) that you plug, well, y= equations. I haven't figured out how to graph binomials or higher, but you can solve them as well in the matrix function. It's pretty cool. And I'm not sure about logarithms...

I took mine earlier this school year and made between 550 and 600. It's not that bad, but I could do better. And for more test tips. Look for things you KNOW can't be right. ie The square root of -9 is... a) 3 b) 18 c) -3 d) 3i It can't be a. You can't have the square root of a negative. Most people will pick it because they see "square root" and "9", bypassing the "-". It can't be b. That is -9 multiplied be -2. It can't be c. A negative squared is a positive. So it must be d. They always do that. Also, when you have the answer, insert it back into the original equation if it involves a variable, and that will help you to get the right answer. I'm getting ready to take my COMPASS, so I'm learning all of this again.

Well, I'm pretty young, so I hope to see it. Own it, or even use it. That'll be pretty cool, but at the rate they're going at, I give it ten, maybe twenty years. Not bad, but i could be wrong. This is for mass production though.

I had one that started off in a "perfect" society, where I was working and I spilled a bucket of paint accidentally, and the coppers were chasing me, and I ended up in the woods and then in a cemetery where other runaways were, and then they caught me in a beat up shack. It inspired me to write a book.

... Why? Just why?

is there anyone here that even believes it?

I don't think it's mole rats, cuz I saw a picture of a litter of more than five. Could it be the kangaroo mouse? Or probably something from Madasgascar.

Oh... Sorry. Forgot. Didn't read the second letter thing.

It could also be "bat" to "cat"....

You look at every number individually. Exponents as a totally different letter, as well as the addition and subtraction signs. Why don't you try it? It only took me about two hours.

nevermind. I got it.

This code was given to me, and I think I may have some of it, but I'm not entirely sure. Can any of you help me to figure this out?

[hide]A 1 The cat was fed milk. 2 The cat went to the litter box. 3 The cat went to where he slept. 4 The cat went to sleep. B 1 The cat walked outside. 2 The cat reached the front gate. 3 The cat slid under the gate. 4 The cat took a walk in the neighborhood. C 1 The cat walked under a car. 2 The cat came from under the car. 3 The cat started running from the dog. 4 The cat hid behind a trashcan to avoid the dog. D 1 The cat started walking home 2 The cat walked on the catwalk. 3 The cat then jumped over the fence. 4 The cat went inside the open door.[/hide] I think that's right...

K. I have a couple other people working on it, and my AVID teacher (don't ask) is the only person who's gotten close on it.