DimaMazin
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Posts posted by DimaMazin
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America created, uses and supports nucklear blackmail policy like all members of nucklear klub . Ukraine destroys the policy . Therefore Trump and all Biden's team are against victory of Ukraine.
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22 minutes ago, Bufofrog said:
The only way that graph makes sense is if t'= -t and x' = -x
Why it cannot be so?
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Let's consider Minkowski diagram with general coordinates of two frames
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15 hours ago, DimaMazin said:
Seems I have got absolutely neutral velocity
V = 2×51/2×c/5
gamma=51/2
Then non-simultaneity
t =t0 + (51/2 - 1)x/(2c)
is absolutely neutral simultaneity.
I cannot correctly make complex exploring therefore that is incorrect.
Let's consider what is quantum velocity. Quantum velosity is velocity which is created by constant and instant acceleration from frame S in frame S' and back. For example velocity between S and S' is v then quantum velocity is v/2. Time of such observer is t/2+t/(2gamma) because the observer has equal time of travel in both frames.
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Seems I have got absolutely neutral velocity
V = 2×51/2×c/5
gamma=51/2
Then non-simultaneity
t =t0 + (51/2 - 1)x/(2c)
is absolutely neutral simultaneity.
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On 11/10/2023 at 3:51 AM, StringJunky said:
A year is a century in politics and 2024 is too far away to call.. Too much can happen, especially at this juncture in human history. I'm much less optimistic for the Dems, since Biden hugged up with Netanyahu.
Rether Biden needs to destroy Iranian nuclear program.
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On 9/15/2023 at 2:28 AM, swansont said:
Three velocities. Two objects. The third is the result of the addition of the two objects' velocities.
My experiment does experimentally define the three velocities. You don't understand my experiment because you don't understand relativity of observers and travelers. Wy the experiment can be bad for Relativity? When the experiment can prove Relativity,if it correct.
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10 hours ago, swansont said:
Why 3? The velocity addition formula is for two objects. But if it works for two (and it does), it will work for three. That’s a math issue, and math works that way.
And you have not provided evidence that there’s a problem.
The equation has three velocities. How do you experimentally define them?
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On 8/24/2023 at 6:21 PM, swansont said:
Since the velocity addition formula can be derived from the Lorentz transforms, this would mean relativity is wrong.
Do you have any experimental evidence of this?
It can be checked experimentaly. 3 travelers is traveling relative to each other. They send light with the same fraquency to each other and resieve the light with other fraquency. Then they can define their velocities and check the laws.
Energy factor has square power of velocity c, therefore delta energy can be variable in different frames. But velocity and gamma factor have unit power in formula of momentum. Because square root annihilate square power. Therefore delta momentum should be constant in any frame.
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37 minutes ago, Genady said:
I have no idea what it means.
On distance 0 time is 0. On distance 1 million km time is 1 second in S frame. What is velocity of non-simultaneity? Non-simultaneity is not velocity but it can have imaging velocity. In frame S' on distanse 0 time is 0 but on what distance and what time was or will be in co-located point relative to second point of frame S?
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1 hour ago, Genady said:
What is it and where was it done? Give the reference.
I have confused. We should create law of addition of non-smultaneities. We can image any velocity(and bigger than c) as non-simultaneity. Then we can check any law of addition of velocities.
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The Einstein's law is incorrect because we cannot use the same module of reverse velocities in two frames. 😝
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17 hours ago, Genady said:
It is called "a wishful thinking."
Yes, i mistaken.
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On 8/21/2023 at 12:39 PM, Genady said:
What does make you think so?
A very simple refutation of Einstein's law of addition of velocities.
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9 hours ago, Genady said:
It needs more clarifications.
When you have got change of momentum dp then any observer,in any frame, defines the your change of momentum as the same dp.
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4 minutes ago, Genady said:
This statement does not make sense.
When they have equal masses.
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1 hour ago, Genady said:
It is not a "correct addition of velocities."
When travelers ,relative to each other , have d momentum then it is the same in any frame.
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3 hours ago, Genady said:
I don't need to think so because there is no conflict between mathematics and physics.
YOUR so-called "laws of physics" are nonsense.
Let's use conservation of momentums for correct addition of velocities
V3×gamma3=v1×gamma1+v2×gamma2
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1 hour ago, Genady said:
Do you think that undefined opinios of mathematicians are more useful in physics than laws of physics?
7 hours ago, studiot said:Consider the following
Let
y=2x−1x
What is y when x = 0 ?
Clue it is not 1 it is about 0.693
For y=x/x
When we approach x to 0 there is no changing of the result.
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5 hours ago, Genady said:
Not any. Only numbers.
You don't know what is 0/0. Then what do you try to explain?
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26 minutes ago, Genady said:
No such thing.
Well. any2×0=0
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58 minutes ago, Genady said:
0/0=1 is wrong everywhere.
Well. 0/0=unknown
Then E1=unknown2×0=0
E2=unknown2×0=0
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22 minutes ago, Genady said:
Which law?
Teachets teached us 0/0=1
What is in Israel?
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22 minutes ago, Genady said:
Tel-Aviv University. Retired.
Do you want to dispruve the law? Or do you remake it?
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War Games: Russia Takes Ukraine, China Takes Taiwan. US Response?
in Politics
Posted
Then Jews were obliged to serch for consensus with Hittler. Due to your wrong policy you do no success in science. Likes of backward Americans led you in delusion.