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s pepperchin

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Posts posted by s pepperchin

  1. Do you discuss only science with everyone you meet and if not what do you discuss with them? I am a physicist and I felt the same way in college, however now that I know a lot of people who are not physicist or even scientist I can use that information to have discussions with them. An example of this is that my fiance is a history teacher and on a few occasions I have been able to offer suggestions for her curriculum based on classes that I took in college. So although you don't like taking the other classes it makes you a well rounded person who people will want to carry on a conversation with.

  2. I started out by adding some labels to your diagram.

     

    triangle circle.jpg

     

    The red letters are the intersection points of the triangle and the circle and the blue letters are variable for the unknown segments.

     

    The length of each of the sides are the same since the triangle is an equilateral.

     

    [math]AD = DG = GA = 16[/math]

    We will need that later.

     

    We will start by solving for W:

     

    We can use the theorem that says for two secant lines that intersect outside of a circle the product of the secant line and the exterior segment of one line are equal to the product of the secant line and exterior segment of the other line.

     

    [math](AH)(AI) = (AC)(AB)[/math]

     

    [math](7+w)(w) = (15)(2)[/math]

     

    This gives us:[math]w=3[/math]

     

    since

     

    [math]v+7+w=16[/math]

     

    [math]v+7+3=16[/math]

     

    [math]v=6[/math]

     

    using the same principle as above for the secant lines from the other angles of the triangle we get:

     

    [math](GH)(GI)=(GF)(GE)[/math]

     

    [math](6)(13)=(y)(y+x)[/math]

     

    [math]y^2 +xy=78[/math] eqtn 1

     

    and

     

    [math](DC)(DB)=(DE)(DF)[/math]

     

    [math](1)(14)=(z)(z+x)[/math]

     

    [math]z^2 + xz =14[/math] eqtn 2

     

    Solving the length of the side [math]x+y+z=16[/math]

    for z

    [math]z=16-x-y[/math] eqtn 3

     

    plug into eqtn 2

     

    [math](16-x-y)^2 + x(16-x-y) =14[/math]

     

    gives us

     

    [math]y=10-\frac{x}{2}[/math]

    plug this into eqtn 3

     

    [math]z=16-x-(10-\frac{x}{2})[/math]

     

    [math]z=16-x-10+\frac{x}{2}[/math]

     

    [math]z=6-\frac{x}{2}[/math]

     

    plug these eqtns for y into eqtns 1

     

    [math]y^2 +xy=78[/math]

     

    [math](10-\frac{x}{2})^2 +x(10-\frac{x}{2})=78[/math]

     

    gives us

     

    [math]x=2 \sqrt{22}[/math]

  3. I use it on a regular basis but mostly for creating graphics. At this point however most of my graphics have been fairly basic. If there are others who are a little more experienced I would be glad to discuss some things with them. There is a mathematica forum however it isn't as nice as here.

  4. If you want to do an interesting experiment with polarization, use corn syrup.

    In one of my lab classes we set a polarizing filter on an overhead projecter, then we poured corn syrup into a shallow glass dish placed on top of the filter, then we would hold the other filter above it and look at the light passing through all three as it is projected on the wall. Ask your teacher about it and maybe he will show you.

  5. C Sharp express is available for download from microsoft. If you are interested in prgramming then you should learn C Sharp. It is easier to use than C. I have been learning C Sharp and I learned a little C a few years ago. C Sharp is easier than C and you can find books that will help you learn it. Try Barnes and Noble or amazon.

  6. [math]y=a^x[/math]

     

    as has already been stated

     

    [math]a^x=e^{xlna}[/math]

     

    we can seperate the exponent into

     

    [math]y=e^xe^{lna}[/math]

     

    and we know

     

    [math]e^{lna}=a[/math]

     

    so that makes our equation for y

     

    [math]y=ae^x[/math]

     

    and we know that the derivative of [math]e^x[/math] is [math]e^x[/math]

    so that

     

    [math]\frac{dy}{dx}=ae^x[/math]

  7. This discovery does not surprise me. As it says in the Bible Genesis Ch3 v14

    "So God said to the serpent' date=' "Because you have done this, 'Cursed are you above all the livestock ...You will crawl on you belly and you will eat dust all the days of your life.[/quote']

     

    What place does a quote from the bible have in a scientific discussion?

  8. the other thing to remember about college is that most schools will give a math placement test to determine what math you have mastered. Usually by the time you are heading into college you have a good enough grasp of algebra, geometry and trig so that you can start with calculus. If however you are going to be a math major than you may take advanced classes that touch on aspects of these subject.

  9. Sorry s pepperchin, just an analogy, not a complete mathematical theory...Imagine the elastic is like space, giving any mass velocity and it will continue at that speed due to inertia. This is of course only until a force acts upon the mass.

     

    I understand the anology, I do have a B.S. in Physics.

  10. TimaLand, I was just thinking if you didnt understand swansont comment about "stress-energy tensor inherent in the mass which causes the gravitational attraction. " If you wanted i propose a simpler, but to may knowledge still accurate with General Relativity, here is it. The Fabric of Spacetime, you could imagine it like a long streched peice of rectangular elastic. If you were to put a mass on it, it would "sink", and place another object close enough, it will slide down. This is the gravataional attraction. The mass bends spacetime. When something else wants to pass near the mass, it falls into the curved spacetime, and will get attracted to it.

     

    What you said is accurate when it comes to an anology to gravity however this example doesn't have a device to introduce cetripital force. Unless of course you have a frictionless elastic sheet so that giving a small mass an initial velocity would keep it moving.

  11. The problem is that you are using the wrong equation.

     

    [math]F_c=ma[/math]

     

    [math]F_c=ma_c[/math]

     

    is correct but to figure out [math]\mu[/math] you use:

     

    [math]F_f=\mu F_N[/math] where [math]F_N=-F_c[/math]

     

    and in order for the person not to slide down the frictioanl force must be equal and opposite to the force of gravity.

     

    [math]F_g=\mu (-F_c)[/math]

     

    [math]m g=\mu (-ma_c)[/math]

     

    [math]g=-\mu a_c[/math]

     

    [math]\mu = \frac{-g}{a_c}[/math]

     

    plug in the numbers

     

    [math]\mu = \frac{-(-9.8\frac{m}{s^2})}{95.5377706\frac{m}{s^2}}[/math]

     

    [math]\mu = .1026[/math]

     

    It is easier to see if you draw it out as you go though.

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