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mrburns2012

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Posts posted by mrburns2012

  1. That's not it. And just so I don't confuse anyone, let me clear up two points.

     

    • By formula I meant what paths/steps got you to the answer.
    • When I asked if any formula can work beyond 20, I asked because I don't know if one exists. Don't take it to mean your formula has to work for numbers over 20 to be correct.

     

    Another hint: there aren't more than 5 steps. For example, n + n + n + n + n + n is already wrong.

     

    I was nine years old at the time I created it. And only knew basic elementary math like subtraction, addition, multiplication, etc.

     

    Well, the most difficult target is a moving one.... :) I'll let someone else pick up the challenge under the new rules.

  2. If an instruction takes 1,000 lines of code to write, using the normal 2 states (1s and 0s), how many lines would the same instruction take to write by a future computer able to use 8 states (various increments of "on/off").

     

    Also, how much would processing speed increase?

     

    Thirdly, would storage capacity (hard drives, disks) be increased any due to the extra states?

     

    Assuming you're using the same programming language, you'd need the the same amount of code. Why? You're changing the nature data is stored on a chip, not the programming language. The advantage of having 8 states would be to increase the amount of data that can be stored on a chip of the same size.

     

    Example (correct me if I'm wrong):

    Let's say you want to store the number 8. In binary code, you'd need 4 "storage spaces" (e.g. 4 surface area units) to store 1,0,0,0 because that's number 8 in binary. When there are 8 states, you'd need 1 storage space to store the number 8. However, if you need to store two pieces of code, "8" and "8" (not the number eighty-eight). You'd need 4 storage spaces for the first "8", another 4 for the other when data is stored in binary states - a total of 8 storage spaces. When there are 8 states, you'd need only 1 storage space for the first 8, and another 1 to store the other 8, hence significantly reducing the amount of storage spaces needed. However, when writing the code on a piece of paper, you'd write 8,8 on either the binary or the 8 states system. They'll just be stored differently.

     

    Processing speed will definitely be increased for the 8 states system (as opposed to the binary system) if the chips for either system can be read or written (i.e. switched to different states) at the same speed, but that's only an "if." The increased speed comes from the fact that there would be less "storage spaces" (e.g. chip surface area) to process.

  3. More specifically an artery................................ I just had surgery and when I saw my GP he said don't worry about the blue thing it will go away. I personally hadn't seen the blue thing until I got a hold of a flash light. It looked very much so like a vein. Knowing some deal about what had been done to me there was no real reason, aside from why a surgeon would leave it exposed, it couldn't be a vein(artery.) It could very well have poped through a seem. When I asked if it was a vein my GP said don't worry about it it's gone. He likes to flat out lie to me, anything to keep me stress free right! I haven't gotten a hold of another flash light so unless I buy one it will be another week 'till I can confirm. Anyway I just thought it was an unusual but interesting thought which was also kind of buging me and thought I might get some feedback from someone. I'm sure historically speaking at some point in time some twisted 'mother just had to test this one out and had taken notes....................

     

    Sometimes veins can be seen through the skin. For example, this guy has veins exposed all over his body: http://en.wikipedia.org/wiki/File:Dexter_Jackson_IFBB_2008_Australia_4.jpg. However, not everyone's the same, so if you suspect that something is not normal, you should look for a second opinion from a different doctor.

  4. I'm no expert, but here's my speculation: a developing embryo is very sensitive to disturbances since its developmental processes require a very precise timing and spatial organization of events. I'd imagine cells that are completely foreign in morphology and composition could could easily disturb (confuse) this process and destroy the embryo immediately, so you'll highly unlikely get anything viable out of the experiment. But even if the embryo is viable for a some period of time, it'll probably develop into something so out of whack it will simply die at a later stage of development. However, a good story here: http://www.foxnews.com/story/0,2933,353884,00.html, suggests that you can have wolf claws as an adult. All you have to do is ask your doctor to fry your immune system and inject some wolf organ stem cells into you.

  5. I really don't get this problem (isn't it from the movie 21, lol?)

     

    What I don't get is how the # of the door affects anything...Idk, just doesn't make sense to me. Maybe I'll get it after some more posts.

     

    The problem:

    Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice? (Whitaker 1990)

     

    The fact that the host always reveal the wrong door affects the outcome. Let me elaborate:

     

    There are 3 doors,

     

    Case 1: You DO NOT switch. You have two scenarios:

     

    1) The probability of choosing the correct door will be 1/3

     

    2) The probability of choosing the incorrect door will be 2/3

     

    Case 2: You DO want to switch:

     

    1) If you had initially picked the incorrect door (probability = 2/3), the chance of changing to the correct door will be 100% since that'll be the only door available after the other incorrect door is revealed.

     

    2) If you had initially picked the correct door (probability = 1/3), the chance of changing to the incorrect door will be also 100% since that's the only door available.

     

    ---

     

    So which method yields the best outcome in these conditions? If you DO NOT switch, you'll have 33% chance of winning (case 1, scenario 1). If you DO switch, you have a 66% chance of winning (case 2, scenario 1). Why? Because you're more likely to choose the incorrect door the first time.

  6. Hello,

     

    My (pseudo)name is Mr. Burns. You can call me Mr. Burns. I'm a student working on a postgraduate degree. My main interest is in the biological sciences. My understanding of the sciences is very basic, so I find this site informative and sometimes entertaining. I look forward to reading more of everyone's contributions to this forum.

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