ku Posted April 30, 2005 Share Posted April 30, 2005 How do you know what limits to put when double integrating. For example for the joint probability distribution function [math]f(x,y)= \begin{cases} 2 & \mbox{if } 0 \leq y \leq x \leq 1\\ 0 & \mbox{elsewhere} \end{cases} [/math] we want to calculate the marginal probability density function of X which is [math]f(x)=\int_{-\infty}^{\infty}f(x,y)dy = \int_{0}^{x}2 dy = 2x[/math]. How come 0 and x are used as limits? Why couldn't we have picked, say, 0 and 1? Link to comment Share on other sites More sharing options...
swansont Posted April 30, 2005 Share Posted April 30, 2005 How do you know what limits to put when double integrating. For example for the joint probability distribution function [math]f(x' date='y)= \begin{cases} 2 & \mbox{if } 0 \leq y \leq x \leq 1\\ 0 & \mbox{elsewhere} \end{cases} [/math'] we want to calculate the marginal probability density function of X which is [math]f(x)=\int_{-\infty}^{\infty}f(x,y)dy = \int_{0}^{x}2 dy = 2x[/math]. How come 0 and x are used as limits? Why couldn't we have picked, say, 0 and 1? Because the value of the function depends on whether y>x or not If the functional value had depended on a hard value for y, you would integrate to that limit. Link to comment Share on other sites More sharing options...
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