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logarithm


md2

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so i remember, logarith is dependence between a to c in a^b = c

so if we have 5 ^ 3 = 125 between 125 and 5 is dependence 125 / 5 = 25, so squart from 2 = 25

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so i remember, logarith is dependence between a to c in a^b = c

so if we have 5 ^ 3 = 125 between 125 and 5 is dependence 125 / 5 = 25, so squart from 2 = 25

 

And your second statement follows from the rule that x^3=(x^2).x - logs dont enter into it

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log10 ( 10 ) = 1, because 10^1=10

log10 ( 100 ) = 2, because 10^2=100

log10 ( 1000 ) = 3, because 10^3=1000

etc.

 

log2 ( 2 ) = 1, because 2^1=2

log2 ( 16 ) = 4, because 2^4=16

log2 ( 256 ) = 8, because 2^8=256

etc.

 

Common bases:

ln(x) = loge(x), base is e

log(x) = log10(x), base is 10

 

In your example, if base is 5, then log5(125)=3

Edited by Sensei
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  • 2 weeks later...

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