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Electrolysis


Highschoolsci187

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I cannot answer your question as asked, so I hope I don't confuse you. If one wants to know how much energy it takes to split water, into H and O, then it will take as much as the energy generated when H and O are combined. Thus, it is possible to burn H2 inside a calorimeter and measure the calories produced per volume of H2 burned. It is possible to convert this value to an amount per atom, and convert calories into any energy unit one wishes. It is an experimental value for the bonding energy, and not exact.

 

Equipment is never perfect and will loose energy to the environment as heat; thus, the energy to split a compound (e.g., H2O) into atoms will require more energy than the bonding energy measured by the calorimeter.

 

I hope I answered the question you asked.

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I cannot answer your question as asked, so I hope I don't confuse you. If one wants to know how much energy it takes to split water, into H and O, then it will take as much as the energy generated when H and O are combined. Thus, it is possible to burn H2 inside a calorimeter and measure the calories produced per volume of H2 burned. It is possible to convert this value to an amount per atom, and convert calories into any energy unit one wishes. It is an experimental value for the bonding energy, and not exact.

 

Equipment is never perfect and will loose energy to the environment as heat; thus, the energy to split a compound (e.g., H2O) into atoms will require more energy than the bonding energy measured by the calorimeter.

 

I hope I answered the question you asked.

i dont want a perfect representation just and equation that wll tell me how much energy it takes to combine/take apart H2O

and an explination of the equation

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