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Proof: C*=C


Endercreeper01

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I have a proof that proves that the conjugate of a complex number is equal to the number. Proof:

  1. You have the complex number a+bi
  2. A+bi is also equal to (i(a+bi))/i
  3. Distributing gives you (ai - b)/i
  4. Distributing the division gives you a - bi

Or, in equation form:

a+bi = (i(a+bi))/i = (ai - b)/i = a - bi

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The mistake happened in step (ai-b)/i = ai-b because they are not equal. You removed a term without even removing i from the top portion.

 

And what do you mean by distributing the division? Do you mean simplifying?

No, it was a - bi

[math] -b/i = +bi \neq -bi [/math]. Not to mention that a simple check whether 0+1i equals 0-1i would have sufficed to sanity-check your alleged proof.

Why does -b/i=bi? Edited by Endercreeper01
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